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Lapatulllka [165]
3 years ago
14

The independent variable of interest in an ANOVA procedure is called a a. partition. b. factor. c. treatment. d. response.

Mathematics
1 answer:
Andru [333]3 years ago
4 0

Answer:

Option b (factor) is the correct choice.

Step-by-step explanation:

ANOVA would be used to assess whenever there were other statistically representative variations seen between results of two or even more individual (totally unconnected) categories.

<u>Two different kinds of independent variables exist such as:</u>

  • Active
  • Reference

If the explanatory variables are such an effective variable otherwise we modify the argument of the variable to test its effect on something like a specific parameter.

Certain solutions don't apply to the specified scenario. So choice B was its perfect method for that.

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The answer is 18
-7^2+4(-7)-3
49+(-28)-3
21-3
18
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Eddie is fishing. He has 1 and one fourth ounces of weight on his line, but his bait isn't getting to the bottom of the lake. Ed
vladimir1956 [14]
1 1/4 + 1/2 + 3/4 = 
5/4 + 1/2 + 3/4 =
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Can someone help me pleaseeeeeeeee.
Leya [2.2K]

Answer:

B) 2.25

Step-by-step explanation:

Given:

x = -2

y = 4

z = -5

Work:

\frac{x^2-z}{y} \\\\\frac{(-2)^2-(-5)}{4}\\\\\frac{4+5}{4} \\\\\frac{9}{4} \\\\2.25

7 0
3 years ago
I need the mid point
Anestetic [448]

Answer:

(14,\frac{-7}{2})

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Midpoint Formula: (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Step-by-step explanation:

<u>Step 1: Define</u>

Point (18, 13)

Point (10, -20)

<u>Step 2: Find Midpoint</u>

Simply plug in your coordinates into the midpoint formula to find midpoint

  1. Substitute [MF]:                    (\frac{18+10}{2},\frac{13-20}{2})
  2. Add/Subtract:                       (\frac{28}{2},\frac{-7}{2})
  3. Divide:                                  (14,\frac{-7}{2})
7 0
3 years ago
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A group of high school athletes has an average GPA of 2.7 with a standard deviation of 0.9. a)Find the percentage of athletes wh
mart [117]

Answer:

a) The percentage of athletes whose GPA more than 1.665 is 87.49%.

b) John's GPA is 3.645.

Step-by-step explanation:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 2.7, \sigma = 0.9

a)Find the percentage of athletes whose GPA more than 1.665.

This is 1 subtracted by the pvalue of Z when X = 1.665. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.665 - 2.7}{0.9}

Z = -1.15

Z = -1.15 has a pvalue of 0.1251

1 - 0.1251 = 0.8749

The percentage of athletes whose GPA more than 1.665 is 87.49%.

b) John's GPA is more than 85.31 percent of the athletes in the study. Compute his GPA.

His GPA is X when Z has a pvalue of 0.8531. So it is X when Z = 1.05.

Z = \frac{X - \mu}{\sigma}

1.05 = \frac{X - 2.7}{0.9}

X - 2.7 = 1.05*0.9

X = 3.645

John's GPA is 3.645.

8 0
3 years ago
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