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Citrus2011 [14]
3 years ago
13

GUYS PLEASE HELP ASAP I WILL MARK BRAINLIEST WITH BEST ANSWER!

Mathematics
2 answers:
Over [174]3 years ago
8 0
So first do 49x3 to see what Henrik has in his other field. 49x3=147 Since Henrik has another field with 173 potatoes you will add them together 173+147=320 potatoes
lubasha [3.4K]3 years ago
3 0
Multiply 49 by 3 and add that answer to 173
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Which of the following is equivalent to (2x + 3)(2x + 3)?
Kryger [21]

Answer:

(2x+3)(2x+3)=4x^2+12x+9

Step-by-step explanation:

we are given

(2x+3)(2x+3)

Firstly, we will distribute it

=2x\times 2x+2x\times 3+3\times 2x+3\times 3

now, we can simplify it

=2\times 2\times x\times x+2\times 3x+3\times 2x+9

=4x^2+6x+6x+9

=4x^2+12x+9

so, we get simplified term as

(2x+3)(2x+3)=4x^2+12x+9

7 0
4 years ago
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He recorded the snowfall for 2 months
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8 0
4 years ago
Question is attached
Neporo4naja [7]

Answer: C

Step-by-step explanation: The standard equation is Ax + By = C

To solve for this, first solve for the slope: y2 - y1 / x2 - x1

0 - 5 / 4 - 0 = -5 / 4

Plug the slope and ordered pair of (0, 5) into the equation y - y1 = m(x - x1)

y - 5 = -5/4(x - 0)

Add 5 to both sides: y = -5/4x + 5

Subtract y and 5: -5 = -5/4x - y

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(or multiply entire equation by -4 to get 20 = 5x + 4y)

7 0
4 years ago
Use Cramer Rule to solve the following system: 8x−5y=70 and 9x+7y=3
nlexa [21]

Answer:

(x,y) = (5,-6)

Step-by-step explanation:

\underline{\textbf{Determinant of a matrix.}}\\\\\text{For a}~ 2 \times 2 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2\\b_1&b_2 \end{vmatrix} = a_1b_2 - a_2b_1\\\\\\\text{For a}~ 3 \times 3 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2&a_3\\ b_1&b_2&b_3\\ c_1&c_2&c_3 \end{vmatrix} = a_1\begin{vmatrix} b_2&b_3\\c_2&c_3 \end{vmatrix} - a_2 \begin{vmatrix} b_1&b_3\\c_1&c_3 \end{vmatrix}+ a_3 \begin{vmatrix} b_1&b_2\\c_1&c_2 \end{vmatrix}\\\\\\

                     ~~~~~~~~~~~~~~~~~~=a_1(b_2c_3-b_3c_2) -a_2(b_1c_3-b_3c_1) +a_3(b_1c_2-b_2c_1)

\underline{\textbf{Cramer's Rule to solve a system of two equations.}}\\\\\text{Consider the system of two equations:}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_1x + b_1 y= c_1\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_2x +b_2 y = c_2\\\\\text{Here,}\\\\x = \dfrac{D_x}{D}= \dfrac{\begin{vmatrix} c_1&b_1\\c_2&b_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\\\ y= \dfrac{D_y}{D}= \dfrac{\begin{vmatrix} a_1&c_1\\a_2&c_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\

\underline{\textbf{Solution:}}\\\\~~~~~~~~~~~~~~~~~~~~~~~8x-5y = 70~~~~~~...(i)\\\\~~~~~~~~~~~~~~~~~~~~~~~9x +7y = 3~~~~~~~...(ii)\\\\\text{Applying Cramer's rule:}\\\\x = \dfrac{D_x}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 70& -5 \\3&7 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{70(7) -(-5)(3)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{490+15}{56+45}\\\\\\~~=\dfrac{505}{101}\\\\\\~~=5

y = \dfrac{D_y}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 8& 70 \\9&3 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{(8)(3) -(70)(9)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{24-630}{56+45}\\\\\\~~=-\dfrac{606}{101}\\\\\\~~=-6

\textbf{Hence, the solution to the system of equation is}~ (x,y) = (5,-6)

7 0
2 years ago
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