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Stels [109]
3 years ago
6

Need helpp fastt plss will give brainliest to who is correct plss helpp

Mathematics
2 answers:
galben [10]3 years ago
8 0

Answer:

The answer is 14.

Step-by-step explanation:

6(2+5)/3 would be the equation

12+30/3

42/3

14

Rina8888 [55]3 years ago
8 0
14 bc 5+2=7 7x6=42 42/3=14
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Py+7=6y+q<br> what is the answer for this question (linear equations with unknown coefficients)?
Temka [501]
Assuming your solving for y:
py+7=6y+q
-6y -7 -6y -7
(p-6)y = q-7
divide both sides by p-6
y=(q-7)/(p-6)
3 0
3 years ago
Read 2 more answers
Three teachers buy prizes to put in the prize bin at school. Mrs. Maiers spends $7.68 on stickers.
SashulF [63]

Hi there! The answer to this problem would be 36.64$.

Step By Step:

So there is three teachers and they all brought something.

_____________________________________

| Mrs.Maiers  | 7.68$                                                |

| Mr.Lang       | 11.52$                                               |

| Mrs.Connor | 17.64$                                              |

______________________________________

Total Cost: 36.64

4 0
3 years ago
In a sample with m = 40 and s = 8, what is the z-score corresponding to x = 38?
Alika [10]
Z = (x - m)/s
z = (38-40)/8
z = -2/8
z = -1/4
z = -0.25

The z score is -0.25
7 0
3 years ago
Read 2 more answers
PLEASE HELP I WILL JIVE YOU 100 POINTS NEEDED ASAP
Anastaziya [24]

Answer:

0.3 galloons of water.

Step-by-step explanation:

We know that 1/5 galloons of water fills 2/3 of the bin.

So, we can write the following fraction:

\frac{\frac{1}{5}\text{ galloons}}{\frac{2}{3}\text{ bin}}

We want to find how many galloons will fill the entire bin or 1 whole bin. So, we can write the following proportion:

\frac{\frac{1}{5}\text{ galloons}}{\frac{2}{3}\text{ bin}}=\frac{x\text{ galloons}}{1\text{ bin}}

To find our answer, we need to solve for x.

So, let's cross-multiply. This yields:

\frac{2}{3}x=\frac{1}{5}

Multiply both sides by 3:

3(\frac{2}{3}x)=3(\frac{1}{5})

The left side simplifies. Multiply on the right:

2x=\frac{3}{5}

Now, multiply both sides by 1/2:

\frac{1}{2}(2x)=\frac{1}{2}(\frac{3}{5})

Simplify the left. Multiply on the right:

x=\frac{3}{10}

So, 3/10 of 0.3 of a gallon of water will fill the entire bin.

And we're done!

3 0
3 years ago
Read 2 more answers
For each part, give a relation that satisfies the condition. a. Reflexive and symmetric but not transitive b. Reflexive and tran
Vesnalui [34]

Answer:

For the set X = {a, b, c}, the following three relations satisfy the required conditions in (a), (b) and (c) respectively.

(a) R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)} is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)} is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)} is symmetric and transitive but not reflexive .

Step-by-step explanation:

Before, we go on to check these relations for the desired properties, let us define what it means for a relation to be reflexive, symmetric or transitive.

Given a relation R on a set X,

R is said to be reflexive if for every a \in X, (a,a) \in R.

R is said to be symmetric if for every (a, b) \in R, (b, a) \in R.

R is said to be transitive if (a, b) \in R and (b, c) \in R, then (a, c) \in R.

(a) Let R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)}.

Reflexive: (a, a), (b, b), (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \implies (b, a) \in R

Therefore R is symmetric.

Transitive: (a, b) \in R \ and \ (b, c) \in R but but (a,c) is not in  R.

Therefore, R is not transitive.

Therefore, R is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)}

Reflexive: (a, a), (b, b) \ and \ (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \ but \ (b, a) \not \in R

Therefore R is not symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)}

Reflexive: (a, a) \in R but (b, b) and (c, c) are not in R

R must contain all ordered pairs of the form (x, x) for all x in R to be considered reflexive.

Therefore, R is not reflexive.

Symmetric: (a, b) \in R and (b, a) \in R

Therefore R is symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is symmetric and transitive but not reflexive .

4 0
3 years ago
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