The steps to construct a regular hexagon inscribed in a circle using a compass and straightedge are given as follows:
1. <span>Construct a circle with its center at point H.
2. </span><span>Construct horizontal line l and point H on line l
3. </span>Label
the point of intersection of the circle and line l to the left of point
H, point J, and label the point of intersection of the circle and line l
to the right of point H, point K.<span>
4. Construct
a circle with its center at point J and having radius HJ .
Construct a circle with its center at point K having radius HJ
5. </span><span>Label
the point of intersection of circles H and J that lies above line l,
point M, and the point of their intersection that lies below line l,
point N. Label the point of intersection of circles H and K that lies
above line l, point O, and the point of their intersection that lies
below line l, point P.
6. </span><span>Construct and JM⎯⎯⎯⎯⎯, MO⎯⎯⎯⎯⎯⎯⎯, OK⎯⎯⎯⎯⎯⎯⎯, KP⎯⎯⎯⎯⎯, PN⎯⎯⎯⎯⎯⎯, and NJ⎯⎯⎯⎯⎯ to complete regular hexagon JMOKPN .</span>
It would be for example: f-25
3y + 12 = 6x
3y = 6x - 12
y = 2x - 4
2y = 4x + (-8)
y = 2x + (-4)....the same as y = 2x - 4
b would have to be a -8
Answer:
just download conects
Step-by-step explanation:
Answer:
j
Step-by-step explanation:
Substitute the given values into x² + x + 1 and check if result is prime
x = - 4
(- 4)² - 4 + 1 = 16 - 4 + 1 = 13 ← prime
(- 2)² - 2 + 1 = 4 - 2 + 1 = 3 ← prime
(- 3)² - 3 + 1 = 9 - 3 + 1 = 7 ← prime
4² + 4 + 1 = 16 + 4 + 1 = 21 ← not prime
x = 4 serves as a counterexample to disprove this conclusion
