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lions [1.4K]
3 years ago
11

A Consider the following method definition. The method printAllCharacters is intended to print out every character in str, start

ing with the character at index 0. public static void printAllCharacters (String str) for (int x = 0; x< str.length(); x++) // Line 3 System.out.print(str.substring(x, x + 1)); The following statement is found in the same class as the printAllCharacters method. printAllCharacters ("ABCDEFG"); Which choice best describes the difference, if any, in the behavior of this statement that will result from changing x < str.length() to x <= str.length() in line 3 of the method?
Α) The method call will print fewer characters than it did before the change because the loop will iterate fewer times.
B) The method call will print more characters than it did before the change because the loop will iterate more times.
C) The method call, which worked correctly before the change, will now cause a run-time error because it attempts to access a character at index 7 in a string whose last element is at index 6.
D) The method call, which worked correctly before the change, will now cause a run-time error because it attempts to access a character at index 8 in a string whose last element is at index 7.
E) The behavior of the code segment will remain unchanged.
Computers and Technology
1 answer:
ozzi3 years ago
7 0

Answer:

<em>(c) The method call, which worked correctly before the change, will now cause a run-time error because it attempts to access a character at index 7 in a string whose last element is at index 6.</em>

<em />

Explanation:

Given

printAllCharacters method and printAllCharacters("ABCDEFG");

Required

What happens when  x < str.length() is changed to x <= str.length()

First, we need to understand that str.length()  gets the length of string "ABCDEFG"

There are 7 characters in "ABCDEFG".

So: str.length()  = 7

The first character is at index 0 and the last is at index 6

Next, we need to simplify the loop:

for (int x = 0; x< str.length(); x++) means for (int x = 0; x< 7; x++)

The above loop will iterate from the character at the 0 index to the character at the 6th index

while

for (int x = 0; x<=str.length(); x++) means for (int x = 0; x<=7; x++)

The above loop will iterate from the character at the 0 index to the character at the 7th index

Because there is no character at the 7th index, the loop will return an error

Hence: (c) is correct

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Answer:

In Python:

nums = []

larg= []

small = []

while True:

   for i in range(10):

       num = int(input(": "))

       nums.append(num)

   print("Smallest: "+str(min(nums))); print("Largest: "+str(max(nums)))

   larg.append(max(nums))

   small.append(min(nums))

   another = int(input("Press 1 to for another sets: "))

   nums.clear()

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Explanation:

This initializes the list of input numbers

nums = []

This initializes the list of largest number of each input set

larg= []

This initializes the list of smallest number of each input set

small = []

This loop is repeated until, it is exited by the user

while True:

The following iteration is repeated 10 times

   for i in range(10):

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Append the smallest to small list

   small.append(min(nums))

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   another = int(input("Press 1 to for another sets: "))

Clear the input list

   nums.clear()

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<em>    if not another == 1:</em>

<em>        break</em>

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print("Average Large: "+str(sum(larg)/len(larg)))

Calculate and print the average of the set of smallest numbers using sum and len

print("Average Small: "+str(sum(small)/len(small)))

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