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Mariana [72]
3 years ago
5

Mhanifa can you please help? Look at the picture attached. I will mark brainliest!

Mathematics
1 answer:
Nikitich [7]3 years ago
4 0

Answer:

<u>Given rhombus ABCD with</u>

  • m∠EAD = 67°, CE = 5, DE = 12

<u>Properties of a rhombus:</u>

  • All sides are congruent
  • Diagonals are perpendicular
  • Diagonals are angle bisectors
  • Diagonals bisect each other

<u>Solution, considering the above properties</u>

  • 1. m∠AED = 90°, as angle between diagonals
  • 2. m∠ADE = 90° - 67° = 23° as complementary of ∠EAD
  • 3. m∠BAE = 67°, as ∠BAE ≅ ∠EAD
  • 4. AE = CE = 5, as E is midpoint of AC
  • 5. BE = DE = 12, as E is midpoint of BD
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We have two fair three-sided dice, indexed by i = 1, 2. Each die has sides labeled 1, 2, and 3. We roll the two dice independent
Nikitich [7]

Answer:

(a) P(X = 0) = 1/3

(b) P(X = 1) = 2/9

(c) P(X = −2) = 1/9

(d) P(X = 3) = 0

(a) P(Y = 0) = 0

(b) P(Y = 1) = 1/3

(c) P(Y = 2) = 1/3

Step-by-step explanation:

Given:

- Two 3-sided fair die.

- Random Variable X_1 : Result on 1st die.

- Random Variable X_2: Result on 2nd die.

- Random Variable X = X_2 - X_1.

Solution:

 

- Possible outcomes of X : { - 2 , -1 , 0 ,1 , 2 }

- The corresponding probabilities for each outcome are:

                 ( X = -2 ):  { X_2 = 1 , X_1 = 3 }  

                P ( X = -2 ):  P ( X_2 = 1 ) * P ( X_1 = 3 )  

                                :  ( 1 / 3 ) * ( 1 / 3 )  

                                : ( 1 / 9 )    

                ( X = -1 ):  { X_2 = 1 , X_1 = 2 } + { X_2 = 2 , X_1 = 3 }

                P ( X = -1 ):  P ( X_2 = 1 ) * P ( X_1 = 3 ) + P ( X_2 = 2 ) * P ( X_1 = 3)

                                :  ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

                                : ( 2 / 9 )        

 ( X = 0 ):  { X_2 = 1 , X_1 = 1 } + { X_2 = 2 , X_1 = 2 } +  { X_2 = 3 , X_1 = 3 }

               P ( X = -1 ):3*P ( X_2 = 1 )*P ( X_1 = 1 )

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               P ( X = 1 ): 2* P ( X_2 = 2 ) * P ( X_1 = 1 )

                                : 2* ( 1 / 3 ) * ( 1 / 3 )

                                : ( 2 / 9 )

                  ( X = 2 ):  { X_2 = 1 , X_1 = 3 }

                 P ( X = 2 ):  P ( X_2 = 3 ) * P ( X_1 = 1 )  

                                   :  ( 1 / 3 ) * ( 1 / 3 )  

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- The distribution Y = X_2,

                         P(Y=0) = 0

                         P(Y=1) =  1/3

                         P(Y=2) = 1/ 3

- The probability for each number of 3 sided die is same = 1 / 3.

8 0
3 years ago
Ignore the answer I put please help and I’ll give brainliest
Leokris [45]

Answer:

B.

Step-by-step explanation:

3/12 reduces to 1/4.

1/2 alone is greater than 1/4, so when 2/10 is added to 1/2, it is certainly greater than 3/12.

Answer: B.

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