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malfutka [58]
3 years ago
12

In your own words describe a fraction is​

Mathematics
2 answers:
Aliun [14]3 years ago
5 0

Answer:

a quantity that is not a whole number

slava [35]3 years ago
4 0

Answer:

A fraction simply tells us how many parts of a whole we have. You can recognize a fraction by the slash that is written between the two numbers. We have a top number, the numerator, and a bottom number, the denominator. For example, 1/2 is a fraction.

Step-by-step explanation:

You might be interested in
What is the value of Point C on the number line below?
natta225 [31]

Answer:

0.28

Step-by-step explanation:

All you need to do is count.

0.20, 0.21, 0.22, 0.23, 0.24, 0.25, 0.26, 0.27, 0.28, 0.29, 0.30

                                                                              <u>C</u>

Point C sits on the point 0.28.

4 0
3 years ago
A website is selling barbecue grills for $783. The site got the barbecue grills at a cost of $580. What is the mark-up, as a per
olasank [31]

Answer:

35%

Step-by-step explanation:

The price it cost the site to buy the grills was $580 but they were selling them for $783. So for each grill, they get a profit of $203. (783-580=203).

35% of $580 is 203 which adds up to $783

So therefore the markup rate is 35% I hope this helps!

5 0
2 years ago
Please answer this ASAP
wlad13 [49]

f(x) = 5x + 1

f(4) = 5 * 4 + 1

f(4) = 20 + 1

f(4) = 21

g(x) = 2x² - 3x +1

g(5) = 5 * 5² - 3 * 5 + 1

g(5) = 125 - 15 + 1

g(5) = 111

f(4) + g(5) = 21 + 111 = 132

6 0
3 years ago
8/3 + 3/4 equals...
Darya [45]

Answer:

Step-by-step explanation:

8/3 + 3/4 =

32/12 + 9/12 =

41/12 = 3 5/12

6 0
3 years ago
Read 2 more answers
You made a square card. The card did not fit in the envelope so you trimmed it. You trimmed 4 inches from the length and 5 inche
ludmilkaskok [199]

Answer:

The original dimensions of the card were 9 inches length and 9 inches width

Step-by-step explanation:

Let x be the original length and width of the card in inches (remember that it was squared originally). The exercise says that the area of the new width, with dimensions x-4 and x-5 is 20 square inches, therefore

(x-4)*(x-5) = 20

x²-9x+20 = 20

x²-9x = 0

x*(x-9) = 0

x = 0 or x = 9

Since x must be positive, then it cant be 0, thus, x has to be 9. The original dimensions of the card were 9 inches length and 9 inches width.

7 0
4 years ago
Read 2 more answers
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