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mart [117]
3 years ago
6

A package of 4 pairs of insulated socks costs ​$21.16. What is the unit price of the pairs of socks​? The unit price is ​$nothin

g per pair of socks.
Mathematics
1 answer:
goldenfox [79]3 years ago
5 0

Unit price is total price/ quantity purchased.

21.16 / 4 = 5.29

Unit price = $5.29 per pair

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The ratio of carbon-14 to carbon-12 in a piece of wood discovered in a cave is R = 1/917. Estimate the age of the piece of wood
Colt1911 [192]

Answer:

The answer is "\bold{6.6 \times 10^{12}\ years}"

Step-by-step explanation:

Let the given value is:

R=\frac{1}{9^{17}}\\\\\to \frac{N_{c_{14}}}{N_{c_{12}}}=\frac{1}{9^{17}}\\\\\to t=\frac{2.303 \times 9^{17}}{5717}=6.6\times 10^{12}\ years

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Find the simple interest for $2,800 at 4% for 4 yrs
SVEN [57.7K]
It would be 2800*0.04*4. Your final answer will be $448
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The graph shows Ms. Padilla's monthly cell phone cost, where x is the number of minutes she uses the phone during the month.
balu736 [363]

Answer: the X intercept mean this here

Ms.

Padilla is charged $0.04/min.

Ms. Padilla pays $16 for months she makes 0 min of calls

Step-by-step explanation:

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1 year ago
Which graph has a slope of 4/5
Lana71 [14]

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Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of 4,000,000 and a mean
In-s [12.5K]

Using the normal distribution, it is found that there is a 0.2776 = 27.76% probability that the life span of the monitor will be more than 20,179 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 19000, \sigma = \sqrt{4000000} = 2000

The probability that the life span of the monitor will be more than 20,179 hours is <u>one subtracted by the p-value of Z when X = 20179</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{20179 - 19000}{2000}

Z = 0.59.

Z = 0.59 has a p-value of 0.7224.

1 - 0.7224 = 0.2776.

0.2776 = 27.76% probability that the life span of the monitor will be more than 20,179 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

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