Part A: D) x is positive, y is negative.
Part B: C) both x and y are negative.
Part A:
P' is found by rotating P 90° counterclockwise about the origin. This makes the coordinates (x,y) transform to (-y,x). Thus (-2,-1) maps to (1,-2).
Part B:
Q'' is found by rotating Q 90° counterclockwise about the origin, then reflecting across the x axis. This makes the coordinates (x,y) first transform to (-y,x), then makes the new y-coordinate the opposite sign. Thus (1,2) first maps to (-2,1), then to (-2,-1).
The perimeter would be about 9 just depends on how you do it
To start, first convert 7x-2y=3 from standard form to slope intercept form. To do this, first subtract over 7x to get -2y=-7x+3. Then, divide both sides by -2 to get
y=7/2x-3/2
Now that you have this in slope intercept form, take the m value of the equation, 7/2 and find the negative reciprocal of it. This will be the value of the slope of a line perpendicular to 7x-2y=3. Your final answer will be -2/7.
Step-by-step explanation:
21
may be, I am not sure about this answer. But it can be