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Ede4ka [16]
2 years ago
12

On a given day, eight rabbits, 12 mice, and four snakes are present on the mountain range. If each animal is equally likely to b

e caught and consumed, what is the probability that the wolf will eat two rabbits?
Mathematics
1 answer:
Tems11 [23]2 years ago
3 0

Answer:

7 / 69

Step-by-step explanation:

Rabbit = 8

Mice = 12

Snake = 4

Total = (8 + 12 + 4) = 24

If each animal has equal probability of being caught ;

Probability of catching a rabbit ;

Number of rabbits / total number of animals

P(catching 1 rabbit) = 8 / 24 = 1/3

P(catching 2nd rabbit) :

Number of rabbits left = 8 - 1 = 7

Total number of rabbits = 24 - 1 = 23

Hence, P(catching 2nd rabbit) = 7 /23

Probability of catching two rabbits :

1 /3 * 7/ 23 = 7 / 69

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