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Anastasy [175]
4 years ago
5

In how many ways can 2 singers be selected from 4 who came for an audition?

Mathematics
1 answer:
Triss [41]4 years ago
7 0

\displaystyle \binom{4}{2}=\dfrac{4!}{2!2!}=\dfrac{3\cdot4}{2}=6

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Which of the following numbers is divisible by 6?
maksim [4K]
The answer is a because when u divide that number by 6 u get a whole number
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3 years ago
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Solve for x in the triangle. Round your answer to the nearest tenth.
hodyreva [135]

Answer:

x ≈ 11.7

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos26° = \frac{adjacent}{hypotenuse} = \frac{x}{13} ( multiply both sides by 13 )

13 × cos26° = x , then

x ≈ 11.7 ( to the nearest tenth )

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3 years ago
it is known that the population proton of utha residnet that are members of the church of jesus christ 0l6 suppose a random samp
Lady_Fox [76]

Answer:

0.0838 = 8.38% probability of obtaining a sample proportion less than 0.5.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Proportion of 0.6

This means that p = 0.6

Sample of 46

This means that n = 46

Mean and standard deviation:

\mu = p = 0.6

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.6*0.4}{46}} = 0.0722

Probability of obtaining a sample proportion less than 0.5.

p-value of Z when X = 0.5. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.5 - 0.6}{0.0722}

Z = -1.38

Z = -1.38 has a p-value of 0.0838

0.0838 = 8.38% probability of obtaining a sample proportion less than 0.5.

8 0
3 years ago
1- Which relation is a function?
babymother [125]

Answer:


Step-by-step explanation:

1. bottom left


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In the figure shown, △BAC ≅ △EDF what is the value of x?
NISA [10]

Step-by-step explanation:

△BAC ≅ △EDF (given)

Therefore,

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x=23

4 0
3 years ago
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