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Mars2501 [29]
3 years ago
11

Find the sum of the first four terms of the geometric series 100 + 50 + 25 + ...

Mathematics
1 answer:
elixir [45]3 years ago
3 0

Answer:

<em><u>Decimal</u></em><em><u>:</u></em>

100 + 50 + 25 + 12.5 + 6.25 + 3.125 + 1.5625

<u><em>Fraction</em></u><u><em>:</em></u>

100 +50+25 + 12\frac{1}{2}+6\frac{1}{4}+3\frac{1}{8}+1\frac{9}{16}

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Find the value of k such that lim--&gt;4 (x^2+x-k)/(x-4) exists
7nadin3 [17]

Answer:

k=20

Step-by-step explanation:

when x approaches 4, the denominator x-4 approaches 0

if the denominator is 0, it means that this is invalid

if the function is a number over 0 when x=4, it represents a vertical asymptote, which means no limit

so the only way possible to let there be a limit is to let the function be 0/0 when we plug in x=4

so x^2 + x - k = 0 when x = 4

4^2 + 4 - k = 0 ==> 20 - k = 0 ==> k = 20

6 0
2 years ago
Which is a zero of the quadratic function f(x) = 9x2 – 54x – 19?
liraira [26]

Answer: Third Choice. x= 6 1/3

Step-by-step explanation:

Given

f(x) = 9x² - 54x - 19

Completing the square

3x          -19

3x          1

Substitute back to the function

f(x) = (3x-19) (3x+1)

Simplify

x= 6 1/3 or -1/3

Hope this helps!! :)

Please let me know if you have any questions

7 0
2 years ago
PLEASE I need help on these 4 problems you don’t have to do them all but if you can at least do one of them TYSM
Brrunno [24]

Answer:

For right angle triangle,

we use Pythagoras theorem that is:

c^{2} =a^{2} +b^{2}

c = \sqrt{a^{2} +b^{2} }

For question 1:

c = ?

a = 40

b = 9

putting them in formula,

c = \sqrt{40^{2} + 9^{2} }

c = 41

For question 2:

c = ?

a = 12

b = 13

putting them in formula,

c = \sqrt{12^{2} + 13^{2} }

c = approximately 17.69181

For question 3:

c = 35

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

35^{2} = 20^{2} + b^{2}

1225 = 400 + b^{2}

b^{2} = 1225 - 400

b^{2} = 825

\sqrt{b^{2} } = \sqrt{825}

b = 5 \sqrt{33}

For question 4:

c = 37

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

37^{2} = 20^{2} + b^{2}

1369 = 400 + b^{2}

b^{2} = 1369 - 400

b^{2} = 969

Taking square root on both sides

b = 31.12

Hope it helps.

4 0
2 years ago
Find the value of the missing coefficient a in the equation y = a(x - 3)(x + 5) if the graph goes through the point (1, -6)
horrorfan [7]

Answer:

3

Step-by-step explanation:

you have to solve for x then you can find the coeeffiecnt

3 0
2 years ago
Need some help please <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B15%7D%20%20%2B%20%28%20-%20%20%5Cfrac%7B3%7D%7B
emmasim [6.3K]

Answer:

-1/60

Step-by-step explanation:

\frac{11}{15}  + (- \frac{3}{4} )\\

= \frac{11}{15}  -  \frac{3}{4}\\

= \frac{44}{60}  -  \frac{45}{60}\\  (find LCM of demoninators)

= \frac{44-45}{60}\\

= \frac{-1}{60}\\

= -1/60

7 0
3 years ago
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