Answer:
google
Step-by-step explanation:
dgodsl,fdrgefsdfvr34ewf
Answer:
1) e = 6
2) w = 10
3) s = 27
4) t = 4
Step-by-step explanation:
Cross multiplication
Answer:
The correct option is 1. The area of cross section area is 48 mm².
Step-by-step explanation:
From the find it is noticed that the cross section is a rectangle with length 4 mm and width is 12 mm.
The area of a rectangle is the product of its dimensions.
Where, l is length of the rectangle and w is width of the rectangle.
The area of cross section is
Therefore the area of cross section area is 48 mm². Option 1 is correct.
Answer:
average atomic mass = 207.2172085 amu
Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.
For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)
The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
+ 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu
Hope this helps :)
Answer:
-2
Step-by-step explanation:
2(x-3), x=2
Since we know what x equals, plug it into the equation
2(2-3)
2(-1)
-2
