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Snowcat [4.5K]
4 years ago
9

A circular pool with a 10 foot diameter is surrounded by a deck.

Mathematics
2 answers:
hichkok12 [17]4 years ago
5 0

Answer:

Step-by-step explanation:

the a square deck as a whole area is 225

side^2 so 15^2

the circles area is 78.54

area of circle formula= pi(r^2)

if you subtract the circle from the squares area you get the outside.

area of deck= 146.46

Mnenie [13.5K]4 years ago
5 0

Answer:

A or 148.5

Step-by-step explanation:

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a quiche with a diameter of 12 inches can feed 6 people. can a quiche with a diameter of 10 inches feed 4 people, assuming the s
Andrew [12]
This is an area problem where the area of a circle is pi*r^2.

A quiche with a diameter of 12 has an area of pi*6^2 = 36pi

So if it can feed 6 people, then the serving size per person is 6pi per person.

A quiche with a diameter of 10 inches has an area of pi*5^2 = 25pi

If each person requires 6pi worth of quiche, then 25pi/6pi = 4 1/6 people.

So yes, it can serve 4 people.
7 0
3 years ago
The cylinder below has r = 10 inches and a volume of 6283 cubic inches to the nearest cubic inch. Find the height of the cylinde
kaheart [24]
V=hpir^2
r=10
v=6283

6283=hpi10^2
6283=100hpi
divide both sides by 100
62.83=hpi
aprox pi=3.141592
divide both sides by pi
19.9994143=h
so about 20 inches
6 0
3 years ago
Write an expression using an expoent that is equivalent to 9x9x9x9x9x9x9.
dexar [7]

Answer:

try nine to the seventh power

Step-by-step explanation:

tell me if it works

4 0
3 years ago
The representation that is used to display the spread of the data is
Vsevolod [243]

Answer:

The spread in data is the measure of how far the numbers in a data set are away from the mean or the median. ... You can also find the spread in the data set by using the interquartile range, which is a value that is the difference between the upper quartile value and the lower quartile value.

Step-by-step explanation:

8 0
3 years ago
A lot of 9 components contains 3 that are defective. Two components are drawn at random and tested. Let be the event that the fi
kirza4 [7]

Answer:

Probabilty of first component drawn defective= 0.1161

Probability of second component drawn defective= 0.1560

Step-by-step explanation:

Total component = 9

Defective component= 3

Non-defective component= 6

Probability of defective= 3/9

= 0.3333

Probabilty of non defective= 1-0.3333

= 0.6666

Probabilty of first component drawn is defective

= 9C1(0.333)¹(0.6666)^8

= 9(0.3333)(0.0387)

= 0.1161

Probabilty of second component is defective

= 8C1(0.3333)¹(0.6666)^7

= 8(0.3333)(0.0585)

= 0.1560

7 0
3 years ago
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