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vazorg [7]
3 years ago
7

6th grade math I mark as brainliest

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
8 0
The answer of this problem is 12:1
lilavasa [31]3 years ago
6 0

Answer:

12:1

Step-by-step explanation:

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6. EVALUATE: -15 + 16 + (-23) - 8<br> NEED ASAP
Sati [7]

Answer:

-30

Step-by-step explanation:

DO YOU REALLY NEED ONE?

4 0
3 years ago
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Round each decimal number to the nearest tenth. Then, select the best estimate for the subtraction equation 1.79 − 0.67 = ___.
nalin [4]

Answer:

1.10

Step-by-step explanation:

1.79

0.67

1.12 rounded is 1.10 to the nearest tenth

3 0
3 years ago
In Buffalo, New York the temperature was -14 F in the morning. If the temperature dropped 7 F, what is the temperature now?
Nata [24]
It would be -14-7 = -21 F
3 0
3 years ago
Read 2 more answers
Emily wins 22000$. She has to pay 10% for charity and then she decides to buy a car for 10800$. She divides the rest of them bet
devlian [24]

Answer:

$7 200

Step-by-step explanation:

Amount of money paid for charity = \frac{10}{100} × $22 000

                                                         = $2 200

Remaining money left for children = $22 000 - $2 200 - $10 800

                                                         = $9000

Let the amount of money her son receives be x and the amount her daughter gets be 4x.

Son's $ + Daughter's $ = $9000

x + 4x = 9000

5x = 9000

Amount of money her daughter gets (4x) = \frac{4}{5} × 9000

                                                                     = $7 200

4 0
3 years ago
The game commission observes the fish population in a stream and notices that the number of trout increases by a factor of 1.5 e
just olya [345]

Answer:

A - f(t)=80(1.5)^t

B - Graph given below

C - Number of trouts in 5th week are 607.2

D - Population of trouts will exceed 500 on the 5th week.

Step-by-step explanation:

We are given that,

The number of trout increases by a factor of 1.5 each week and the initial population of the trout is observed to be 80.

Part A: So, the explicit formula representing the situation is,

f(t)=80(1.5)^t, where f(t) represents the population of trouts after 't' weeks.

Part B: The graph of the function can be seen below.

It can be seen that the function is an exponential function.

Part C: It is required to find the number of trouts in the 5th week.

So, we have,

f(5)=80(1.5)^5

i.e. f(5)=80\times 7.59

i.e. f(5) = 607.2

Thus, the number of trouts in 5th week are 607.2

Part D: We are given that the trout population exceeds 500.

It is required to find the week in which this happens.

So, we have,

50

i.e. (1.5)^t>\frac{500}{80}

i.e. (1.5)^t>6.25

i.e. t\log 1.5>\log 6.25

i.e. t\times 0.1761>0.7959

i.e. t>\frac{0.7959}{0.1761}

i.e. t > 4.5

As, t represents the number of weeks. So, to nearest whole, t = 5.

Thus, the population of trouts will exceed 500 on the 5th week.

7 0
3 years ago
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