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a_sh-v [17]
2 years ago
5

Solve this I need it solved

Mathematics
1 answer:
gizmo_the_mogwai [7]2 years ago
8 0

Answer:

option 3

Step-by-step explanation:

Standard \ quadratic \ equation : ax^2 + bx +c

Larger the value of  '' a '' makes the parabola narrow.

A positive value of '' a '' which is close to 0 makes the parabola wide.

<em><u>To find the widest graph , find the smallest </u></em><em><u>a</u></em><em><u>. (or </u></em><em><u>a</u></em><em><u> closest to zero)</u></em>

option 1

     a_1 = \frac{1}{3}

option 2

     a_2 = - \frac{4}{5}

option 3

     a_3 = 0.3 = \frac{3}{10}

option 4

     a_4 = -4

Positive and negative value of ' a ' decides the direction the parabola opens.

But we have to find the widest parabola irrespective of the direction.

So we will find the smallest  ' a '

                                a_1 = 0.33\\a_2 = 0.80\\a_3 = 0.30\\a_4 = 4

a_3 \ is \ the \  smallest \  number \  or\ \\ the \  number \  closest \  to\  zero.\\\  so \  option \ 3 \ makes\  the\  widest \ parabola.

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What is the product of (y + 3) and (7y – 1)?
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Answer: =7y^2+20y−3

Step-by-step explanation:

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3 years ago
Investment A 50 increases each year by 8% investment B 60 increases by 3 each year what year will investment A be bigger than be
UkoKoshka [18]

Answer:

After 10 years the investment A will be bigger than investment B.

Step-by-step explanation:

In Investment A, 50 increases each year by 8% and in investment B, 60 increases by 3 each year.

If after x years the investment A will be equal to investment B, then we can write the equation as

50(1 + \frac{8 \times x}{100}) = 60 + 3x

⇒ 50 + 4x = 60 + 3x

⇒ x = 10

Therefore, after 10 years the investment A will be bigger than investment B. (Answer)

6 0
3 years ago
Can someone help me with this one I would appreciate it very much!!
jekas [21]

Answer:

12.5 pounds

Step-by-step explanation:

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6 0
2 years ago
Faced with rising fax costs, a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail inste
Vladimir [108]

Answer:

The value of t test statistics is 5.9028.

We conclude that the true mean is greater than 10 at the .01 level of significance.

Step-by-step explanation:

We are given that a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail instead.

The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample mean of 14.44 with a standard deviation of 4.45 pages.

<em />

<em>Let </em>\mu<em> = true mean transmission of pages.</em>

So, Null Hypothesis, H_0 : \mu \leq 10 pages     {means that the true mean is smaller than or equal to 10}

Alternate Hypothesis, H_A : \mu > 10 pages     {means that the true mean is greater than 10}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = 14.44 pages

            s = sample standard deviation = 4.45 pages

            n = sample of fax transmissions = 35

So, <u><em>test statistics</em></u>  =  \frac{14.44-10}{\frac{4.45}{\sqrt{35} } }  ~ t_3_4  

                               =  5.9028

(a) The value of t test statistics is 5.9028.

Now, at 0.01 significance level the z table gives critical values of 2.441 at 34 degree of freedom for right-tailed test.

<em>Since our test statistics is more than the critical values of z as 5.9028 > 2.441, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis.</u></em>

Therefore, we conclude that the true mean is greater than 10.

(b) Now, P-value of the test statistics is given by the following formula;

               P-value = P( t_3_4 > 5.9028) = Less than 0.05%    {using t table)

7 0
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Dilution Problem
LUCKY_DIMON [66]

Answer:

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Step-by-step explanation:

You have ...

  C1×V1 = C2×V2

so ...

  V2 = V1×(C1/C2) = (115 L)×(14/21) = 76 2/3 L

  V2 ≈ 76.7 L

4 0
3 years ago
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