Question

Solve this I need it solved

Answer 1

Answer:

option 3

Step-by-step explanation:

$Standard \ quadratic \ equation : ax^2 + bx +c$

Larger the value of  '' a '' makes the parabola narrow.

A positive value of '' a '' which is close to 0 makes the parabola wide.

To find the widest graph , find the smallest a. (or a closest to zero)

option 1

     $a_1 = \frac{1}{3}$

option 2

     $a_2 = - \frac{4}{5}$

option 3

     $a_3 = 0.3 = \frac{3}{10}$

option 4

     $a_4 = -4$

Positive and negative value of ' a ' decides the direction the parabola opens.

But we have to find the widest parabola irrespective of the direction.

So we will find the smallest  ' a '

                                $a_1 = 0.33\\a_2 = 0.80\\a_3 = 0.30\\a_4 = 4$

$a_3 \ is \ the \ smallest \ number \ or\ \\ the \ number \ closest \ to\ zero.\\\ so \ option \ 3 \ makes\ the\ widest \ parabola.$