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kumpel [21]
3 years ago
5

Jill has a jar full of dimes and quarters. If she has a total of $27.20 and the number of quarters is less than twice the dimes,

how many of each coin are in the jar?
Mathematics
1 answer:
Levart [38]3 years ago
5 0

Answer: She has 76 dimes and 78 quarters.

Step-by-step explanation:

Given data:

Total = $27.20

Solution:

Q = d + 2

Each quarter is 25 cents, or 0.25 of a dollar = 0.25q

Each dime is 10 cents = 0.10d

0.25q+0.10d = $27.20

Where q = d-2

Substitute in this equation:

0.25(d+2)+0.10d = 27.20

0.25d + 0.5 + 0.10d = 27.20

0.35d = 26.7

Divide both sides by 0.35

d = 76

She has 76 dimes and 76 + 2 = 78 quarters.

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