3 years ago

Plz help ASAP!!!! I NEED IT!!!!!If you don't know the answer plz don't use an answer to say "oh idk" or sum like that

Mathematics

1 answer:

Monica [59]3 years ago

7 0

Answer:

I wanna say the first picture second answer choice. Please tell me if I am right.

Step-by-step explanation:

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Let f(x) = x + 7 and g(x) = x − 4. Find f(x) ⋅ g(x).

saveliy_v [14]

For this case we have the following functions:

$f (x) = x + 7\\g (x) = x-4$

We must find the product of the functions:

$f (x) * g (x) = (x + 7) (x-4)$

We apply distributive property:

$f (x) * g (x) = x ^ 2-4x + 7x-28\\f (x) * g (x) = x ^ 2 + 3x-28$

Finally, the product of the functions is:

$x ^ 2 + 3x-28$

Answer:

$x ^ 2 + 3x-28$

6 0

3 years ago

What is the altitude of a rhombus if its area is 50 square meters and the length on one side is 12.5 meters

SVETLANKA909090 [29]

<u>Answer:</u>

8 meters or 4 meters

<u>Step-by-step explanation:</u>

We know that for finding the area of a rhombus, there are two diagonal sides: one of which is 12.5 meters in length and the other one we'll assume to be y.

Then, we can write:

Area of rhombus = $\frac{1}{2} *12.5*y$

$50=\frac{1}{2} *12.5*y$

$y=\frac{100}{12.5}$

$y=8$ meters

If the sides of the rhombus are not internally diagonal, then we can simply use the following formula:

Area of rhombus = altitude * side

$50=a*12.5$

$a=4$ meters

3 0

3 years ago

Read 2 more answers

18/4 leave your answer in fraction

Ipatiy [6.2K]

Answer:

18/4

Step-by-step explanation:

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3 years ago

for a stem competition julienne constructed a model rocket the rocket can reach an average height of 545 ft. Find the difference

zhenek [66]

We have the following table:
545-534.2 = 10.8
545-556.4 = -11.4
545-554.0 = -9
545-535.3 = 9.7
write them as a positive and negative rational numbers
positive:
9.7 = 9 7/10
10.8 = 10 4/5
negative:
-11.4 = -11 2/5
-9 = -9
the differences from least to greatest
-11 2/5
-9
9 7/10
10 4/5

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3 years ago

If the difference of 1 9/13 - 6/7, Bruno's answer- too high-too low-correct

alexgriva [62]

Too highhhhhhhhhhhhh

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3 years ago