The value of c such that the function f is a probability density function is 2
<h3>How to determine the value of c?</h3>
The density function is given as:
f(x) = cxe^(−x^2) if x ≥ 0
f(x) = 0 if x < 0.
We start by integrating the function f(x)
∫f(x) = 1
This gives
∫ cxe^(−x^2) = 1
Next, we integrate the function using a graphing calculator.
From the graphing calculator, we have:
c/2 * (0 + 1) = 1
Evaluate the sum
c/2 * 1 = 1
Evaluate the product
c/2 = 1
Multiply both sides of the equation by 2
c = 2
Hence, the value of c such that the function f is a probability density function is 2
Read more about probability density function at
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Answer:
12
Step-by-step explanation:
(10/y + 13) -3
Let y=5
(10/5 + 13) -3
PEMDAS says parentheses first
(2 +13) -3
15 -3
12
Oops wrong question I answered, Sorry.
Answer:
<h3>The greatest common factor of 30, 48 and 2 is 2</h3>
Step-by-step explanation:
<h2>I HOPE IT HELPS </h2>
Radius is 5 cm. is the answer
