Answer:
The length of segment DA is 15 units
Step-by-step explanation:
- <em>The segment which joining a vertex of a triangle and the midpoint of the opposite side to this vertex is called a median </em>
- <em>The point of intersection of the median of a triangle divides each median into two parts the ratio between them is 1: 2 from the base, which means </em><em>the length of the median is 3 times the part from the base</em><em> </em>
Let us use this rule to solve the question
In Δ AEC
∵ D is the midpoint of EC
∴ AD is a median
∵ B is the midpoint of AC
∴ EB is a median
∵ F is the midpoint of AE
∴ CF is a median
→ The three medians intersected at a point inside the triangle,
let us called it M
∵ AD ∩ EB ∩ CF at M
∴ M is the point of intersection of the medians of Δ AEC
→ By using the rule above
∴ AD = 3 MD
∵ MD = 5
∴ AD = 3(5)
∴ AD = 15 units
5.76 KG as 180 x 0.032 (3.2 percent) = 5.76
Answer:
I'm pretty sure it's -3/2
20 is the answer pls seee
The vertex of the given parabola is the point (3, 25).
<h3>
How to get the vertex of the parabola?</h3>
If the parabola has roots x₁ and x₂, then the vertex of the parabola is at:
xₙ = (x₁ + x₂)/2
Here the parabola is:
y = (-2 - x)*(x - 8)
We can rewrite that to:
y = -(x + 2)*(x - 8)
Then the two roots are:
x = -2 and x = 8
Then the vertex is at:
xₙ = (8 - 2)/2 = 6/2 = 3
To get the y-value of the vertex, we evaluate the equation in x = 3:
y = -(3+ 2)*(3 - 8) = -5*(-5) = 25
The vertex is (3, 25).
If you want to learn more about parabolas:
brainly.com/question/4061870
#SPJ1
