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BigorU [14]
3 years ago
10

Pls help urgently extra points and mark brainlist

Mathematics
2 answers:
slavikrds [6]3 years ago
6 0
7 is the prime factor of 210
Ipatiy [6.2K]3 years ago
3 0

Answer:

The answer is 7

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SAT scores are normed so that, in any year, the mean of the verbal or math test should be 500 and the standard deviation 100. as
vovangra [49]

Answer:

a) P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)

P(Z>1.25)=1-P(Z

b) P(400

P(-1

P(-1

c) z=-0.842

And if we solve for a we got

a=500 -0.842*100=415.8

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the SAT scores of a population, and for this case we know the distribution for X is given by:

X \sim N(500,100)  

Where \mu=500 and \sigma=100

We are interested on this probability

P(X>625)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)

And we can find this probability using the complement rule and with the normal standard table or excel:

P(Z>1.25)=1-P(Z

Part b

We are interested on this probability

P(400

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(400

And we can find this probability with this difference:

P(-1

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-1

Part c

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.8   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.2 of the area on the left and 0.8 of the area on the right it's z=-0.842. On this case P(Z<-0.842)=0.2 and P(Z>-0.842)=0.8

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.842

And if we solve for a we got

a=500 -0.842*100=415.8

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.  

8 0
3 years ago
A contractor is building a new subdivision on the outside of a city. He has started work on the first street and is planning for
kotegsom [21]

Answer:

it is c. x + y = −6    

Step-by-step explanation:

i took the test

6 0
3 years ago
Which sequence of transformations carries ABCD onto HGFE
trasher [3.6K]
If you look closely at the options, the first 3 options will not produce an image that will be in Quadrant II with the vertices coinciding HGFE.
But if you look at the 4th option, translating the points 8 units to the left will produce an image in Quadrant III. Reflecting the image across the x-axis will produce triangle HGFE.
7 0
3 years ago
Read 2 more answers
I don’t 100% remember how to turn this into a standard problem.. could someone help me really quick?
marin [14]
Standard form is ax^2+bx+c=0

First evaluate the exponent and expand (foil).
y= 3(x^2-4x+4)+1

Then distribute the 3
y= 3x^2-12x+12+1

Combine like terms
y=3x^2-12x+13

Final answer: 3x^2-12x+13=0
6 0
3 years ago
Find the greatest common factor of the following mononmials : u^2v^2 , 11u^2v^5
weeeeeb [17]

Answer:

1

Step-by-step explanation:

Since there are no common prime factors, the only common factors for both monomials are 1, therfore they stay as they are, 11u²v⁵ and u²v².

I am joyous to assist you anytime.

3 0
3 years ago
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