Answer:
6
Step-by-step explanation:
Substitute n for 3
A(n) = 3/2(-2)^(n-1)
A(3) = 3/2(-2)^(3-1)
A(3) = 3/2(-2)²
A(3) = 3/2(4)
A(3) = 12/2
A(3) = 6
Probability that no zebras collide is 0.25
The zebras are represented as z1, z2 and z3.
Z1 to B, Z2 to C, and Z3 to A come first 
Following that, z1 to C, z2 to A, and z3 to B = 
Consequently, the likelihood of no collision is 2×1/8 = 0.25.
<h3>
What are the types of probability distributions ?</h3>
Discrete and continuous probability distributions are the two main categories in which probability distributions fall. There are numerous varieties of probability distributions within each category.
- The number of favorable outcomes of an event divided by the total number of possible outcomes of an event can be used to calculate the probability of an event.
- The likelihood of a sure or certain event is one.
- The likelihood of an impossibility is 0 (0).
- Every event has a probability between 0 and 1.
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Answer:
9
Step-by-step explanation:
18/2=9
Oh wait. I am wrong
Answer:
The remainder is: 3x+3
The quotient is: 1
Step-by-step explanation:
We need to divide
(3x^2 + 9x + 7) by (x+2)
The remainder is: 3x+3
The quotient is: 1
The solution is attached in the figure below.
This is the concept of polynomials, to get the relationship between the (x-3) and (x^3+4x^2+2) we shall proceed as follows;
we first test if (x-3) is a polynomial;
x-3=0
thus;
x=3
substituting the value of x in the polynomial we get:
(3)^3+4(3)^2+2
=65
since the result is not equal to 0, we conclude that there is no relationship between (x-3) and the polynomial. The answer is B. (X-3) is not a factor