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3 years ago

What are the zeros of the following quadratic equation: y = 6x2 - 17x - 3

Mathematics

1 answer:

Mama L [17]3 years ago

5 0

Answer:

$\displaystyle x=-\frac{1}{6}, 3$

Step-by-step explanation:

Hi there!

$y = 6x^2 - 17x - 3$

Factor by grouping:

$y = 6x^2 - 18x+1x - 3\\y = 6x(x- 3)+1x - 3\\y = 6x(x- 3)+(x - 3)\\y = (6x+1)(x- 3)$

Let y=0. Apply the zero product property:

$0 = (6x+1)(x- 3)$

$6x+1=0\\6x=-1\\\\\displaystyle x=-\frac{1}{6}$

AND

$x-3=0\\x=3$

I hope this helps!

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Step-by-step explanation:

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