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erik [133]
3 years ago
6

What are the zeros of the following quadratic equation: y = 6x2 - 17x - 3

Mathematics
1 answer:
Mama L [17]3 years ago
5 0

Answer:

\displaystyle x=-\frac{1}{6}, 3

Step-by-step explanation:

Hi there!

y = 6x^2 - 17x - 3

Factor by grouping:

y = 6x^2 - 18x+1x - 3\\y = 6x(x- 3)+1x - 3\\y = 6x(x- 3)+(x - 3)\\y = (6x+1)(x- 3)

Let y=0. Apply the zero product property:

0 = (6x+1)(x- 3)

6x+1=0\\6x=-1\\\\\displaystyle x=-\frac{1}{6}

AND

x-3=0\\x=3

I hope this helps!

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