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3 years ago

For y=3x+5, find the rangevalue the domain value is 5.I NEED IT ASAP

Mathematics

2 answers:

liubo4ka [24]3 years ago

6 0

Answer: 20

Step-by-step explanation: Have a great night

bogdanovich [222]3 years ago

4 0

Answer:

y = 20

Step-by-step explanation:

y = 3x + 5 If x = 5

y = (3*5) + 5

y = 15 + 5

y = 20

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7. Find x if the perimeter of the equilateral triangle is 77. Equation: Solution: Round to the nearest hundredth. 6.5X minus 1

stealth61 [152]

If the perimeter of equilateral triangle is 77 and the equation showing the perimeter is 6.5X-1 then the value of X is equal to 12.

Given that the perimeter of equilateral triangle is 77 and the expression showing the perimeter is 6.5X-1.

We are required to find the value of X which is used in the expression.

Expression is combination of numbers, fraction, coefficients, indeterminants, determinants, which are mostly not found in equal to form.

Perimeter which is given is 77 and 6.5X-1.

6.5X-1=77

6.5X=77+1

6.5X=78

X=78/6.5

X=12

Hence if the perimeter of equilateral triangle is 77 and the expression showing the perimeter is 6.5X-1 then the value of X is equal to 12.

Learn more about equation at brainly.com/question/2972832

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2 years ago

33-6(1 1/3+ 2/3)= ? what does it equal?

belka [17]

33 - 6(1 1/3 + 2/3)
33 - 6 ( 1 3/3)
33 - 6 ( 2)
33 - 12
21

hope this helps! : D

7 0

4 years ago

Hey get you points <br> hahahaha

Juli2301 [7.4K]

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3 years ago

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harina [27]

Answer:

Step-by-step explanation:

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4 years ago

Read 2 more answers

3^(x-2) = 5^(x+1)

Molodets [167]

Answer:

$x=log_{\frac{3}{5} }(45)$

$x-2=log_{3}(5)x+log_{3}(5) \\x-log_{3}(5)x=log_{3}(5)+2\\(1-log_{3}(5))x=log_{3}(5)+2\\x=\frac{log_{3}(5)+2}{1-log_{3}(5)} \\x=\frac{log_{3}(5)+log_{3}(3^2)}{log_{3}(3)-log_{3}(5)} \\x=\frac{log_{3}(5x3^2)}{log_{3}(\frac{3}{5} )} \\x=\frac{log_{3}(5x9)}{log_{3}(\frac{3}{5} )} \\x=\frac{log_{3}(45)}{log_{3}(\frac{3}{5} )}\\x=log_{\frac{3}{5}}(45)$

Hope this helps you :)

8 0

3 years ago