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3 years ago

7

Does anybody know how to do that

2 answers:

viva [34]3 years ago

6 0

There is no question attached

irinina [24]3 years ago

5 0

Answer:

how to do what? there is no question attached

Step-by-step explanation:

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What is the radius of a sphere if its surface area is 2,122.64 square inches? (Use 3.14 for π.) 11 in. 13 in. 121 in. 169 in.

crimeas [40]

To solve this, we are going to use the surface are of a sphere formula: $A=4 \pi r^2$
where
$A$ is the surface area of the sphere
$r$ is the radius of the sphere

We know for our problem that $A=2122.64$ and $\pi =3.14$ , so lets replace those vales in our formula:
$A=4 \pi r^2$
$2122.64=4(3.14)r^2$
$2122.64=12.56r^2$
Now, we just need to solve our equation for $r$ :
$\frac{2122.64}{12.56} =r^2$
$r^2=\frac{2122.64}{12.56}$
$r^2=169$
$r=+or- \sqrt{169}$
$r=13$ or $r=13$
Since the radius of a sphere cannot be a negative number, $r=13$ .

We can conclude that the radius of a sphere with surface area <span>2,122.64 </span> $in^2$ is 13 in.

3 0

3 years ago

Which angle is vertical to <br><br> (Will reward)

xenn [34]

The angle vertical to it is DF

3 0

3 years ago

Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

3 years ago

B) The following patterns are made using small squares.

kotegsom [21]

Answer:

(N+2)^2+6

Step-by-step explanation:

8 0

2 years ago

Evaluate the expression 5t + 2m for m = 7 and t = 2.

pantera1 [17]

Answer:

<h3>The answer is 24</h3>

Step-by-step explanation:

5t + 2m

m = 7 t = 2

Substitute the above values into the expression

That's

5(2) + 2(7)

10 + 14

24

Hope this helps you

5 0

4 years ago