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2 years ago

Does anybody know how to do that

Mathematics

2 answers:

viva [34]2 years ago

6 0

There is no question attached

irinina [24]2 years ago

5 0

Answer:

how to do what? there is no question attached

Step-by-step explanation:

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Lim x tends to π÷2 , then what is the value of (tanx + cotx) ÷ ( tanx - cotx)

KiRa [710]

(tan(x) + cot(x)) / (tan(x) - cot(x)) = (tan²(x) + 1) / (tan²(x) - 1)

… = (sin²(x) + cos²(x)) / (sin²(x) - cos²(x))

… = -1/cos(2x)

Then as x approaches π/2, the limit is -1/cos(2•π/2) = -sec(π) = 1.

8 0

2 years ago

What number is 4 units to the right of 5 on the number line

mart [117]

Answer:

Step-by-step explanation:

$4 \: units \: to \: the \: right \: of \: 5 \\ = 5 + 4 = 9$

8 0

3 years ago

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e

Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in $\mu g/mL$

$C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})$

Thus, we are given the time interval [0,12] for t.

We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

$\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})$

Equating the first derivative to zero, we get,

$\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0$

Solving, we get,

$8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2$

At t = 0

$C(0) = 8(e^{(0)}-e^{(0)}) = 0$

At t = 2

$C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185$

At t = 12

$C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059$

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

4 0

2 years ago

BRAINLIEST FOR AN ACTUAL ANSWER

Andreyy89

Answer:

The correct pair of functions is the third one: h(x)=(x−24)^2 and g(x)=x2

Step-by-step explanation:

Example: If we have q(x) = x^2 and its graph, moving the vertex of this graph 24 units to the right results in r(x) = (x - 24)^2.

The correct pair of functions is the third one: h(x)=(x−24)^2 and g(x)=x2

Note: the fourth pair is incorrect, because the " + " sign moves the graph of x^2 24 units to the left.

3 0

2 years ago

Is this a linear function? One person sends an email to 2 people. Those 2 people send it to 4 people, and those 4 send it to 8 p

Mumz [18]

Yes; this is a linear function because you plug in a number and multiply it by two, so the function would be y=2x, which is linear despite the fact that it lacks a b value.

Hope this helps! :)

8 0

3 years ago