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3 years ago

What's the Pythagorean Theorem?

Mathematics

1 answer:

Lady_Fox [76]3 years ago

5 0

Answer:

The pythagorean theorem is a^2 + b^2 = c^2

Step-by-step explanation:

Not sure what you're asking! Sorry! :)

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15x – 7 = 4x – 18<br> What is x

Triss [41]

Answer:

x = - 1

Step-by-step explanation:

Given

15x - 7 = 4x - 18 ( subtract 4x from both sides )

11x - 7 = - 18 ( add 7 to both sides )

11x = - 11 ( divide both sides by 11 )

x = - 1

3 0

3 years ago

I need help<br> someone pls

Alborosie

Answer:

≈ 66.5 m

Step-by-step explanation:

Using the sine ratio in the right triangle

sin12° = $\frac{opposite}{hypotenuse}$ = $\frac{d}{320}$ ( multiply both sides by 320 )

320 × sin12° = d , then

d ≈ 66.5 m ( to 1 dec. place )

8 0

3 years ago

-1+3cotx <br> How do I graph this?

True [87]

Desmos it’s super easy just type it in and it will give explanation

4 0

3 years ago

Read 2 more answers

Sketch each line and find the slop and Y-intercept

Anon25 [30]

Lol where the problem

6 0

4 years ago

You might need: CalculatorThe angle O, is located in Quadrant III, and sin((.)1213What is the value of cos((,)?Express your answ

Wewaii [24]

We know that:

$\sin (\theta_1)=-\frac{12}{13}$

There is also an interesting property that relates the sine and the cosine of an angle:

$\sin ^2(\theta_1)+\cos ^2(\theta_1)=1$

We can find the cosine of theta using this equation:

$\begin{gathered} \cos ^2(\theta_1)=1-\sin ^2(\theta_1) \\ \cos (\theta_1)=\sqrt{1-\sin^2(\theta_1)} \\ \cos (\theta_1)=\sqrt[]{1-(-\frac{12}{13})^2} \\ \lvert\cos (\theta_1)\rvert=\sqrt[]{1-\frac{144}{169}}=\sqrt[]{\frac{25}{169}} \\ \lvert\cos (\theta_1)\rvert=\frac{5}{13} \end{gathered}$

Since theta is in the third quadrant then its cosine must be a negative number so:

$\cos (\theta_1)=-\frac{5}{13}$

3 0

1 year ago