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Lubov Fominskaja [6]
3 years ago
8

Can someone help me asap please

Mathematics
1 answer:
nikklg [1K]3 years ago
8 0

Answer:

Here you go. It is really easy. All you have to do is translate the points. If it says translate 3 units up, you'd pick a point, and move it up 3 units. Then do it with all the others and BOOM! You did it! Try one of the problems yourself to make sure you understand what to do next time.

Have a nice day!

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The length is b 12 !
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3 years ago
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2cos^2x+cosx-1=0<br> Find the degree solutions
Lapatulllka [165]
2cos²x+cos x-1=0

cos x=t

2t²+t-1=0

t=[-1⁺₋√(-1+8)]/2=(-1⁺₋3)/4
We have two possible set solutions:
First set solutions.
t₁=(-1-3)/2=-4/4=-1   
cos x=-1  ⇒x=cos⁻¹ (-1)=π +2kπ    or     180º+360ºk    (k=(...-2,-1,0,1,2...)

Second set solutions:
t₂=(-1+3)/4=2/4=1/2

cos x=1/2  ⇒ x=cos⁻¹ 1/2=π/3+2kπ   U   5π/3+ 2kπ   or
60º+360ºK  U 300º+360ºK        (k=...-2,-1,0,1,2,...)

solutions: first set solutions U second set solutions:

Answer in radians : π +2kπ U π/3+2kπ U 5π/3+ 2kπ   (k=...-1,0,1,...)
Answer is degrees: 180º+360ºk U 60º+360ºK  U 300º+360ºK        (k=...-2,-1,0,1,2,...)
4 0
3 years ago
When the outliers are removed, how does the mean change? (2 points) dot plot with 1 on 50, 1 on 76, 1 on 78, 2 on 79, 1 on 80, 1
777dan777 [17]

Answer:

Answer: The mean increases by 3

Step-by-step explanation:

The original data set is 

{50, 76, 78, 79, 79, 80, 81, 82, 82, 83}

The outlier is 50 because it is not near the group of values from 76 to 83 which is where the main cluster is.

The original mean is M = (50+76+78+79+79+80+81+82+82+83)/10 = 77

If we take out the outlier 50, the new mean is N = (76+78+79+79+80+81+82+82+83)/9 = 80

So in summary so far

old mean = M = 77

new mean = N = 80

The difference in values is N-M = 80-77 = 3

So that's why the mean increases by 3

8 0
3 years ago
Which of the following functions is graphed below?
-BARSIC- [3]

A) first choice because for x=0 the y= 5 and for x=2 the y=3

4 0
3 years ago
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