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3 years ago

15

Please look at the box

2 answers:

jenyasd209 [6]3 years ago

6 0

Answer:

m = slope

(x_1, y_1) = coordinates of first point in the line

(x_2, y_2) = coordinates of second point in the line

vekshin13 years ago

5 0

Answer:

what that person said

Step-by-step explanation:

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A growing farming conglomerate increases its water usage at a rate of 5% every year. If it used 48,000 megaliters of water this

romanna [79]

Answer:

Future requirement of water = 115,517 mega-liters

Step-by-step explanation:

Given:

Current requirement of water (C) = 48,000 mega-liters

Increasing rate per year (g) = 5% = 0.05

Number of year (n) = 18 years

Find:

Future requirement of water = ?

Computation:

$Future\ requirement\ of\ water = C(1+g)^n\\\\Future\ requirement\ of\ water = 48,000(1+0.05)^{18}\\\\ Future\ requirement\ of\ water = 48,000(1.05)^{18}\\\\ Future\ requirement\ of\ water = 48,000(2.4)\\\\Future\ requirement\ of\ water = 115,517 (Approx)$

Future requirement of water = 115,517 (Approx) mega-liters

7 0

3 years ago

Find an equation of the circle having the given center and radius.<br> Center (-7, 6), radius 6

Basile [38]

Answer:

36 = (x+7)^2 + (y-6)^2

Step-by-step explanation:

6^2=(x-(-7))^2 + (y-6)^2

4 0

2 years ago

It’s algebra 2! help asap plzz

san4es73 [151]

This is the difference of two perfect cubes.

(6y-4)(36y^2+24y+16)

3 0

3 years ago

The image below is an example of what construction?

Neko [114]

Answer:

a regular hexagon

Step-by-step explanation:

6 corners

4 0

2 years ago

Find all the zeroes of the equation(with simple steps).

uysha [10]

<u>Answer-</u>

<em>The zeros are, $5,\ -5,\ 4i,\ -4i$ </em>

<u>Solution-</u>

$\Rightarrow -3x^4+27x^2+1200=0$

$\Rightarrow -3(x^2)^2+27(x^2)+1200=0$

Here,

a = -3, b = 27, c = 1200

So,

$x^2=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\dfrac{-27\pm \sqrt{-27^2-4\cdot (-3)\cdot 1200}}{2\cdot (-3)}$

$=\dfrac{-27\pm \sqrt{729+14400}}{-6}$

$=\dfrac{-27\pm 123}{-6}$

$=\dfrac{-27+123}{-6},\ \dfrac{-27- 123}{-6}$

$=\dfrac{96}{-6},\ \dfrac{-150}{-6}$

$=-16,\ 25$

So,

$\Rightarrow x^2=25,\ -16$

$\Rightarrow x=\sqrt{25},\ \sqrt{-16}$

$\Rightarrow x=5,\ -5,\ 4i,\ -4i$

8 0

3 years ago