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vodka [1.7K]
3 years ago
6

Write the expression nine divided by the quantity of x plus y

Mathematics
1 answer:
seropon [69]3 years ago
7 0

9514 1404 393

Answer:

  \text{A)}\quad\dfrac{9}{x+y}

Step-by-step explanation:

In the English expression, you need to understand that "A divided by B" means that A is the numerator and B is the denominator of the fraction representing the division. Here, "B" is "the quantity of ...", which means that the stuff after "of ..." is to be treated as a single item, the denominator in this case. That item is "x plus y." So, the expression in math terms is ...

  \dfrac{9}{x+y}

When this is written in plain text, the "quantity" is put in parentheses, because the fraction bar no longer serves as a grouping symbol:

  9/(x+y)

These expressions match the first choice, A.

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8 0
3 years ago
Find the value of x for which the function y = x5-x³ + x² - 1 has a local minimum.
melisa1 [442]

The given function presents a local minimum in the coordinates (0,-1).

<h3>Factoring</h3>

In math, factoring or factorization is used to write an algebraic expression in factors. There are some rules for factorization.  One of them is a factor out a common term for example: x²-x= x(x-1), where x is a common term.

For solving this question, the given equation should be rewritten  from the factoring.

x^5-x^3+x^2-1=\left(x+1\right)^2\left(x-1\right)\left(x^2-x+1\right)=0. Then, you have 3 equations.

From the Zero Factor Principle, you can write

Equation 1

(x+1)²=0

x+1=0

x= -1

Equation 2

x-1=0

x=1

Equation 3

x²-x+1=0

x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\ \\ x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{3}i}{2\cdot \:1}

From these points it is possible to plot a graph and you can see that the local minimum presents the coordinates (0,-1).

Read more about the factoring here:

brainly.com/question/11579257

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7 0
2 years ago
How you solve this by using solving proportions
DerKrebs [107]

3/(x + 4) = (x + 2)/5

Multiply both sides by 5 :

5 × 3/(x + 4) = 5 × (x + 2)/5

15/(x + 4) = x + 2

Multiply both sides by x + 4 :

(x + 4) × 15/(x + 4) = (x + 4) × (x + 2)

Provided that x + 4 ≠ 0, we can cancel the factors of x + 4 on the left side:

15 = (x + 4) (x + 2)

Expand the product on the right side:

15 = x² + 6x + 8

Move everything to one side:

0 = x² + 6x - 7

We can factorize easily in this case
0 = (x + 7) (x - 1)

Then

x + 7 = 0   or   x - 1 = 0

⇒   x = -7   or   x = 1

7 0
2 years ago
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