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nexus9112 [7]
3 years ago
7

I'll give u branley: A recipe calls for 10 cups of flour to make 60 pancakes. How many pancakes can be made with a single cup of

flour?
Mathematics
2 answers:
ki77a [65]3 years ago
5 0

Answer:

6 pancakes

Step-by-step explanation:

60 divided by 10 is 6.

Tatiana [17]3 years ago
3 0

Answer: 6

Step-by-step explanation:

60/10 is 6

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A farmhouse shelters 10 animals. Some are pigs and some are ducks. Altogether there are 36
riadik2000 [5.3K]

Answer: pigs = 8 , ducks =2

Step-by-step explanation:

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86, 82, 78, 74 , what is the 40th sequence
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Answer:

The numbers slowly decrease by 4 so we can determine that the 40th sequence is -70.

Step-by-step explanation:

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3 years ago
Determine the equation of the line for the given information: the graph has y-intercept (0,6) and contains the point (2,1)
ivanzaharov [21]

Answer:

B is the answer

Step-by-step explanation:

you are given two points (0,6) and (2,1)

the equation is y=mx+b it says that the graph has a y-intercept (0,6) from this point you take the y-value which is also ur b-value in the equation to find m you need to do y2-y1/x2-x1

6 0
3 years ago
9.
Masja [62]

Answer: The Answer is D.

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8 0
4 years ago
A courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the
Rasek [7]

Answer:

\mu_{p} = p = 0.06

And the standard error is given by:

SE_{p} = \sqrt{\frac{\hat p(1-\hat p)}{n}}

And replacing we got:

SE_[p]= \sqrt{\frac{0.06*(1-0.06)}{373}}= 0.0123

And we want to find this probability:

P(\hat p < 0.03)

We can calculate the z score for this case and we got:

z = \frac{\hat p -\mu_p}{\Se_p} = \frac{0.03-0.06}{0.0123}= -2.440

And using the normal distribution table or excel we got:

P(\hat p < 0.03)= P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

For this case we can find the mean and standard error for the sample proportion with these formulas:

\mu_{p} = p = 0.06

And the standard error is given by:

SE_{p} = \sqrt{\frac{\hat p(1-\hat p)}{n}}

And replacing we got:

SE_[p]= \sqrt{\frac{0.06*(1-0.06)}{373}}= 0.0123

And we want to find this probability:

P(\hat p < 0.03)

We can calculate the z score for this case and we got:

z = \frac{\hat p -\mu_p}{\SE_p} = \frac{0.03-0.06}{0.0123}= -2.440

And using the normal distribution table or excel we got:

P(\hat p < 0.03)= P(Z

8 0
4 years ago
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