There are 3 main processes in urine formation. These are Filtration, reabsorption and secretion.
Filtration
Blood enters the afferent arteriole and goes to glomerulus where blood is filtered and it will sip inside the glomerulus and nonfilterable components will go into efferent arteriole.
Reabsoprtion
Molecules and ions will be reabsrobed into the system. The fluid will pass into the proximal, distal and convoluted tubules, loop of henle, as water an ions are removed as the fluid osmolarty changes. Last is secretion of substance that is not filtered.
Answer:
She should get Earth spinning on its axis again.
Explanation:
I just did it on edguenity
The genealogy tree which is missing from the question is in the attachment.
Answer: 1) P1 = ; 2) P2 = ; 3)P3 =
Explanation: 1) According to the genealogy tree, the individual III-3 has a P1 = 1/2, because each of the parents are heterozygous for the condition, since one of the ofspring is affected.
2) For individual III-4, one of the parents is heterozygous for the condition, so the probability of being a carrier is P2 = 1/2.
3) Now, for individual IV-1 be affected, the parents has to be carrier. So, this probability, depends on the probability of each parent being heterozygous and that the individual will be carrying the condition, which means:
P3 = 1/2 · 1/2 · 1/4 = 1/16.
The probability of having the condition is 1/16 or 6.25%.
omg... that's really hard and i don't know what the answer is.
Explanation:
by the way, thanks for points