Answer:
Second puck travels farther
Step-by-step explanation:
Maximum height of first puck = 3 feet
The height of a second hockey puck is modeled by:


To find maximum height of second puck

Equate the derivative equals to 0
0.15-0.002x=0

75 = x
At x = 75

So, The maximum height of second puck is greater than first puck
So, Second puck travels farther
Slope (m) =0
θ =180°
distance (d) =15
ΔX =15
ΔY =0
The relation of t as in to what?
If a line is parallel to another line,Then the gradients are the same.So m=4 .Using general formula for str8 line, y=mx+c

sub in coorfinates (1,13)

So C=9.