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2 years ago

26 multiplied by 16 what’s the answer

Mathematics

2 answers:

natali 33 [55]2 years ago

5 0

Answer:

416

Step-by-step explanation:

Flauer [41]2 years ago

3 0

Answer:

416

Step-by-step explanation:

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What’s is 65% of 208

Marrrta [24]

1352.2 or

$\frac{673}{5}$

Step-by-step explanation:

$\frac{65}{100} \times 208 = answer$

7 0

3 years ago

In the figure below determine the midpoints

Digiron [165]

Midpoints are points in the middle, so I believe they are Midpoints: D, F and E

3 0

2 years ago

#1: Solve the inequality below.<br> -3x + 5 < -19

frosja888 [35]

Explanation: Just like any of your two-step equations,

in this inequality, start by isolating the x term which in this

case is -3x by subtracting 5 from both sides.

That leaves you with -3x < -24.

To get x by itself, divide both sides by -3 but watch out.

When you multiply or divide both sides of an inequality by a

negative number, you must switch the direction of the inequality sign.

So we have x < 8 and put your final answer in

set notation and it look like this → {x: x < 8}.

4 0

3 years ago

The square below represents one whole.

grandymaker [24]

Answer:

Fraction: 81/100

Decimal: 0.81

Percentage: 81%

Step-by-step explanation:

The question is complete but the diagram mentioned can be found in

brainly.com/question/12188410

First step is to find the area of the whole square and then the area of the part that was shaded.

From the diagram, there are 100 squares in the whole square. 81 of those squares are shaded.

Area of the whole square = 10 by 10

= 10×10 = 100unit²

Area of shaded region = (10 by 8) + 1

= 80+1 = 81unit²

shaded area expressed as a fraction = 81unit²/100unit²

= 81/100

Shaded area expressed as a decimal = 81/100

You take the number 81 and carry the point by two decimal place from the right

= 0.81

Shaded area expressed as a percent of the whole = (81/100) × 100

= (81×100)/100

= 81%

6 0

2 years ago

A rectangle has a length 6 more than it's width if the width is decreased by 2 and the length decreased by 4 the resulting has a

Rashid [163]

Answer:

Length of original rectangle: 11 units.

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

$\text{Perimeter of new rectangle}=20$

Step-by-step explanation:

Let x represent width of the original rectangle.

We have been given that a rectangle has a length 6 more than it's width. S the length of the original rectangle would be $x+6$ .

We have been given that when the width is decreased by 2 and the length decreased by 4 the resulting has an area of 21 square units.

The width of new rectangle would be $x-2$ .

The length of new rectangle would be $x+6-4=x+2$ .

The area of new rectangle would be $(x+2)(x-2)$ .

Now we will equate area of new rectangle with 21 and solve for x as:

$(x+2)(x-2)=21$

Applying difference of squares, we will get:

$x^2-2^2=21$

$x^2-4=21$

$x^2-4+4=21+4$

$x^2=25$

Since width cannot be negative, so we will take positive square root of both sides.

$\sqrt{x^2}=\sqrt{25}$

$x=5$

Therefore, the width of original rectangle is 5 units.

Length of the original rectangle would be $x+6\Rightarrow x+5=11$ .

Therefore, the length of original rectangle is 11 units.

$\text{Area of original rectangle}=5\times 11$

$\text{Area of original rectangle}=55$

Therefore, area of the original rectangle is 55 square units.

Now we will find ratio of the original rectangle area to the new rectangle area as:

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

We know that perimeter of rectangle is two times the sum of length and width.

$\text{Perimeter of new rectangle}=2((x+2)+(x-2))$

$\text{Perimeter of new rectangle}=2((5+2)+(5-2))$

$\text{Perimeter of new rectangle}=2(7+3)$

$\text{Perimeter of new rectangle}=2(10)$

$\text{Perimeter of new rectangle}=20$

Therefore, the perimeter of the new rectangle is 20 units.

7 0

3 years ago