Answer:
A. 2·x² + 16·x + 32 ≥ 254
Step-by-step explanation:
The given dimensional relationship between the dimensions of the photo in the center of the cake and the dimensions of the cake are
The width of the cake = The width of the photo at the center of the cake, x + 4 inches
The length of the cake = 2 × The width of the cake
The area of the cake Wanda is working on ≥ 254 in.²
Where 'x' represents the width of the photo (at the center of the cake), let 'W' represent the width of the cake, let 'L' represent the length of the cake, we get;
W = x + 4
L = 2 × W
Area of the cake, A = W × L ≥ 254
∴ A = (x + 4) × 2 × (x + 4) = 2·x² + 16·x + 32 ≥ 254
The inequality representing the solution is therefore;
2·x² + 16·x + 32 ≥ 254
Answer:
Option C) Critical value is based on the significance level and determines the boundary for the rejection region
Step-by-step explanation:
Critical Value:
- In hypothesis testing, a critical value is a point that is compared to the test statistic
- It is used to determine whether to reject the null hypothesis or accept the null hypothesis.
- If the absolute value of your test statistic is greater than the critical value,we fail to accept the null hypothesis and reject it.
- Critical value is affected by the significance level of the testing.
- It is the value that a test statistic must exceed in order for the the null hypothesis to be rejected.
Thus, option C) is the correct interpretation of critical values.
Option C) Critical value is based on the significance level and determines the boundary for the rejection region
Bria: 145 centimeters
Jayleen: 1.5 meters
I'm going to convert Jayleen's into centimeters:
1 meter has 100 centimeters
1.5 x 100 = 150 centimeters
so,
Bria:145 centimeters
Jayleen: 150 centimeters
So, Jayleen bought more fabric
ALWAYS TRUE
Step-by-step explanation:
Because there is no value of x
Answer:
The minimum distance (perihelion) of Uranus from the sun is 2,749,040,972.
Step-by-step explanation:
Consider the provided information.
The length of the half of the major axis is 2,876,769,540 kilometers, and the eccentricity is 0.0444.
The eccentricity (e) of an ellipse is the ratio of the distance from the center to the foci (c) and the distance from the center to the vertices (a).
Substitute a = 2,876,769,540 and e = 0.0444 in above formula and solve for c.
Minimum distance of Uranus from the sun is:
Hence, the minimum distance (perihelion) of Uranus from the sun is 2,749,040,972.
