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ANTONII [103]
3 years ago
12

Please help-help-help

Mathematics
1 answer:
Mrac [35]3 years ago
8 0

Answer:

both I think hope u get it right

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Ent<br> =<br> Solve for x.<br> 4(x + 1) &lt; 4x + 3
Igoryamba

Answer:

x=allrealsolutions

Step-by-step explanation:

5 0
3 years ago
Kelly went to a hockey game with her family. They bought 4 bags of cotton candy and 2 souvenir cups and spent $36. Marissa's fam
erik [133]
4b+2c=36, solve for b, subtract 2c from both sides

4b=36-2c  divide both sides by 4

b=9-0.5c

Then we are told that:

7b+3c=59, using b=9-0.5c we get:

7(9-0.5c)+3c=59  perform indicated multiplication on left side

63-3.5c+3c=59  combine like terms on left side

63-0.5c=59  subtract 63 from both sides

-0.5c=-4 divide both sides by 0.5

c=8

So each souvenir cup costs $8.

(and each bag of cotton candy is $5)
3 0
3 years ago
HELP
Triss [41]

Answer:

  • 42390 ft³

Step-by-step explanation:

Since the tanks are congruent, they both have same volume.

If you rejoin them, it will form a cylinder with the radius of 15 ft and height of 120 ft.

<u>The volume of the cylinder:</u>

  • V = πr²h = 3.14*15²*120 = 84780 ft³

<u>The volume of each tank is half the volume of the cylinder:</u>

  • V(tank) = 84780 / 2 = 42390 ft³
5 0
3 years ago
Read 2 more answers
Simplify: 6 x (-5)+(-18)​
faust18 [17]

Answer:

-138

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Can someone help me out with some pesky math quiz :) I put a pic
Sindrei [870]

1. Simplifying ∛54 gives 3∛2

2. 27^1/3 * (27)^3 is equal to  27

3. The expression (2j4k)^4/5 can be written as \sqrt[4]{32j^{20}k^{5}  }^{5} making the first option the correct option

4. simplifying \sqrt[4]{16x^{4} y^{12} } will result to 2x∛y

5. simplifying \sqrt[5]{2940x^{13} y^{7} } will result to 14x^{6} y^{3} \sqrt{15xy} making the last option the correct option

<h3>How to simplify \sqrt[5]{2940x^{13} y^{7} }</h3>

<u>given data</u>

\sqrt[5]{2940x^{13} y^{7} }

= ( 2940 * x^13 * y^7 )^1/5

=  ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5}

=  ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5*5/2}

=  ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{5/5*1/2}

multiplying the values inside the parenthesis by ^1/2

= ( 2 * 5^{1/2} * 3^{1/2} * 7 * x^{6} * x^{1/2} * y^3 * y^{1/2} )

= ( 2 * 5^{1/2} * 3^{1/2} * 7 * x^{6} * x^{1/2} * y^3 * y^{1/2} )

= ( 14* 5^{1/2} * 3^{1/2} * x^{6} * x^{1/2} * y^3 * y^{1/2} )

= ( 14 * x^6 * y^3 ) ( 5^{1/2} * 3^{1/2}  * x^{1/2} * y^{1/2} )

= ( 14x^6y^3 ) ( 15^{1/2} * x^{1/2} * y^{1/2} )

= ( 14x^6y^3 ) ( 15xy)^{1/2}

= ( 14x^6y^3 ) \sqrt{( 15xy)}

we can therefore say that the last option is the answer

Read more on equations here: brainly.com/question/22688504

#SPJ1

3 0
1 year ago
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