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stepladder [879]
3 years ago
7

How can I learn the heart of algebra in 3 days for my PSAT ​

Mathematics
1 answer:
alexgriva [62]3 years ago
3 0

Answer:

google and watch You tube videos

Step-by-step explanation:

You might be interested in
Find perimeter of rectangle when length = 4.6m and breadth = 360cm​
ivann1987 [24]

Answer:

16.4 m²

Step-by-step explanation:

length = 4.6 m

breadth = 360 cm = 360 ÷ 100 = 3.6 m

Perimeter = 2*(l + b)

                 = 2 * ( 4.6 + 3.6)

                 = 2 * 8.2

                  = 16.4 m²

7 0
2 years ago
Read 2 more answers
Need help on this question
Sedaia [141]

Answer:

A

Step-by-step explanation:

Hey There!

So these triangles are congruent so segment CD is equal to segment DB

so to find x we use the equation

7x+10=10x+7

now we solve for x

step 1 subtract each side by 7

10-7=3

7-7 cancels out

now we have 7x+3=10x

step 2 subtract each side by 7 x

10x-7x=3x

7x-7x= cancels out

now we have

3x=3

step 3 divide each side by 3

3/3=1

3/3 cancels out

now we have

x=1

3 0
3 years ago
Read 2 more answers
Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
Has this app helped u​
pochemuha

Answer:

Discoveries and scientific and technical inventions do not influence the behavior of people, but their lives do

Step-by-step explanation: what app and ok

6 0
2 years ago
Read 2 more answers
How do you do 27 divided by 624 in partial quotients
Virty [35]

Answer:

Step-by-step explanation:

For this case we have the following numbers:

624

27

When dividing both numbers, we observe that:

The partial quotient of the division is equal to 23

The rest of the division is equal to 3.

Note: See attached image to see the procedure of the division between both numbers.

Answer:

the partial quotient of 624 divided by 27 is:

23

6 0
3 years ago
Read 2 more answers
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