The graph is **increasing on the interval (-2, 1)**because the graph has a positive slope from x=-2 to x=1. It’s **decreasing at the intervals (-infinity, -2) and (1, infinity)**because the graph has a negative slope between the x values -infinity to -2 and is also decreasing between the x values of 1 and infinity.
Y^2+4y=-8
add 8 both sides
y^2+4y+8=0 in the form of ax²+bx+c=0
Factor it
by formula
-b+-(√b²-4ac)/2a
-4+-(√16-32)/2*1
-4+-(√-16)/2
-4+-4i/2
-2+-2i where√-1=i
11/15=.7333333 so the one with the line above the 3 only
The given inequality is:

This inequality can be divided in two parts as:
a)

b)

Solving part a:

Solving part b:

Therefore, the solution to the given inequality is

and

. Combining both the ranges we get the solution:

.
In interval notation, this solution can be expressed as [1,5]