You would use the distributive property.
Let x = length of the park
Let y = width of the park
Because the area is 392392 ft², therefore
xy = 392392 (1)
Because three sides of fencing measure 5656 ft, therefore
2x + y = 5656 (2)
That is
y = 5656 - 2x (3)
Substitute (3) into (1).
x(5656 - 2x) = 392392
5656x - 2x² = 392392
2x² -5656x + 392392 = 0
x² - 2828x + 196196 = 0
Solve with the quadratic formula.
x = (1/2)*[2828 +/- √(2828² - 4*196196)]
= 2756.83 or 71.17
Answer:
The possible dimensions are 2756.8 ft and 71.2 ft (nearest tenth)
Answer: 195 CM
Step-by-step explanation:
Volume: Length x Width x Height
“First we have to break it into 2 shapes”
“Let’s solve the top shape!!”
The length is 5 the width is 3 and the height is 4.
Volume = 5 x 3 x 4 = 60
Now the bottom shape
The length is 9 the Width is 5 and the Height is 3
The height isn’t given so we must do some math
Subtract the 7 from 4 = 7 - 4 = 3
Volume = 9 x 5 x 3 = 135
Finally, 135 + 60 = 195 cm
24=2(w+4)+2w=4w+8, subtract 8 from both sides 4w=16, w=4. L=w+4 so l is 8. The dimensions are 8 by 4.
A=bh. You are trying to find the missing dimension which is height. You can set up an equation. 18.7=17h. Divide 18.7 by 17, and you get 1.1, so the height is 1.1
