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3 years ago

What is the height of a triangle of base 10m and an area of 60m²

Mathematics

2 answers:

GuDViN [60]3 years ago

3 0

A = 0.5*b*h

60 = 0.5*10*h

60 = 5h

5h = 60

h = 60/5

h = 12

Answer: The height is 12 meters.

NNADVOKAT [17]3 years ago

3 0

Answer:

6 m

Step-by-step explanation:

Since the area is 60 m squared and the base is 10 m, the height is 12.

Formula: base x height / 2 = area

= 10 x height / 2= 60 m squared

60 / 10 = 6 x 2 = 12.

Hope this helps!

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Step-by-step explanation:

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3 years ago

A rumor spreads through a small town. Let y ( t ) be the fraction of the population that has heard the rumor at time t and assum

Ivan

Answer:

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solution

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Step-by-step explanation:

We know

y(t): proportion of people that heard the rumor

y'(t)=ky(1-y), rate of spread of the rumor

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solving the differential equation

$\frac{dy}{y(1-y)}=k\cdot dt \\\\\int \frac{dx}{y(1-y)} =k \int dt \\\\-ln(1-\frac{1}{y} )+C_0=kt\\\\1-\frac{1}{y} =Ce^{-kt}\\\\\frac{1}{y} =1-Ce^{-kt}\\\\y=\frac{1}{1-Ce^{-kt}}$

Initial conditions:

$y(0)=0.2\\y(3)=0.4\\\\y(0)=0.2=\frac{1}{1-Ce^0}\\\\1-C=1/0.2\\\\C=1-1/0.2= -4\\\\\\y(3)=0.4=\frac{1}{1+4e^{-3k}} \\\\1+4e^{-3k}=1/0.4\\\\e^{-3k}=(2.5-1)/4=0.375\\\\k=ln(0.375)/(-3)=0.327\\\\\\y=\frac{1}{1+4e^{-0.327t}}$

Value of constant k=0.327 days^(-1)

At what time the rumor reaches 80%?

$y(t)=0.8=\frac{1}{1+4e^{-0.327t}} \\\\1+4e^{-0.327t}=1/0.8=1.25\\\\e^{-0.327t}=(1.25-1)/4=0.0625\\\\t=ln(0.0625)/(-0.327)=8.48$

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3 years ago

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Step-by-step explanation:

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3 years ago

What is the height of a triangle of base 10m and an area of 60m²​

What is the height of a triangle of base 10m and an area of 60m²