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ASHA 777 [7]
3 years ago
5

Find ML, JK=3x+11, ML=10x-12, NP=45

Mathematics
1 answer:
tigry1 [53]3 years ago
5 0

Answer:

ML = 58

Step-by-step explanation:

Given

JK=3x+11, ML=10x-12, NP=45

See attachment

Required

Length ML

First, calculate x using the following equivalent ratios

JK : NP = NP : ML

Express as fraction

\frac{JK }{ NP} = \frac{NP }{ ML}

Cross Multiply

JK * ML = NP * NP

Substitute values:

(3x +11) * (10x - 12) = 45 * 45

Expand

30x^2 - 36x + 110x - 132 = 2025

30x^2 +74x - 132 = 2025

Collect like terms

30x^2 +74x - 132 - 2025=0

30x^2 +74x -2157=0

Using a calculator:

x \approx -10 and x \approx 7

Given that:

ML=10x-12

Substitute values for x

ML=10*-10-12 = -100 - 12 = -112

ML=10*7-12 = 70 - 12 = 58

ML cannot be negative; So:

ML = 58

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A ship sails 250km due North qnd then 150km on a bearing of 075°.1)How far North is the ship now? 2)How far East is the ship now
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Answer:

1)  288.8 km due North

2)  144.9 km due East

3)  323.1 km

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Step-by-step explanation:

<u>Bearing</u>: The angle (in degrees) measured clockwise from north.

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

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  • O is the side opposite the angle
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<u>Cosine rule</u>

c^2=a^2+b^2-2ab \cos C

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Draw a diagram using the given information (see attached).

Create a right triangle (blue on attached diagram).

This right triangle can be used to calculate the additional vertical and horizontal distance the ship sailed after sailing north for 250 km.

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To find how far North the ship is now, find the measure of the short leg of the right triangle (labelled y on the attached diagram):

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Then add it to the first portion of the journey:

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<u>Question 2</u>

To find how far East the ship is now, find the measure of the long leg of the right triangle (labelled x on the attached diagram):

\implies \sf \sin(75^{\circ})=\dfrac{x}{150}

\implies \sf x=150\sin(75^{\circ})

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To find how far the ship is from its starting point (labelled in red as d on the attached diagram), use the cosine rule:

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Therefore, the ship is 323.1 km from its starting point.

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