<span>These ones are correct:
Multiply the value of the first variable by one of the original equations to solve for the second variable.
</span><span>Solve for one of the variables
</span><span>Substitute the value of the known variable into one of the original equations to solve for the unknown variable.</span>
The expression for the distance from the 1st base to the 3rd base in terms of side length will be c=x√2
Given that the softball diamond is square in shape.
Let the side of the square i.e. distance between consecutive bases is x
The distance from the 1st base to the 3rd base creates the hypotenuse of a right triangle, where each side is equal to x i.e. x is the side length of the square formed by the baseball diamond.
Using the Pythagorean theorem we have:
x² +x²= c²,
where c is the distance from the 1st base to the 3rd base.
Combining similar terms gives us
2x²=c²
Taking the square root of both sides we have
√2x²= √c²
⇒x√2=c
⇒c=x√2
This is the expression for the distance from the 1st base to the 3rd base in terms of side length.
Therefore the expression for the distance from the 1st base to the 3rd base in terms of side length will be c=x√2.
Learn more about the Pythagorean theorem
here: brainly.com/question/231802
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<span>You have:
- The diameter of the cylinder is 12 inches and its height is 14 inches.
-The height of the cone is 6 inches.
So, you must apply the formula for calculate the volume of the cylinder a the formula for calculate the volume of a cone.
V1=</span>πr²h
<span>
V1 is the volume of the cylinder.
r is the radius.
h is the height (h=14 inches)
The problem gives you the diameter, but you need the radius, so you have:
r=D/2
r=12 inches/2
r=6 inches
When you substitute the values into the formula, you obtain:
V1==</span>πr²h
V1=(3.14)(6 inches)²(14 inches)
V1=1582.56 inches³<span>
The volume of the cone is:
V2=(</span>πr²h)/3
<span>
V2 is the volume of the cone.
r is the radius (r=6 inches)
h is the height of the cone (h=6 inches).
Then, you have:
</span>
V2=(πr²h)/3
V2=(3.14)(6 inches)²(6 inches)/3
V2=226.08 inches³
<span>
Therefore, </span>the volume of the cake<span> (Vt) is:
Vt=V1+V2
Vt=</span>1582.56 inches³+226.08 inches³
<span> Vt=1808.6 inches</span>³
Answer:
B.
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