I need help with number 5
2 answers:
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The formula for the radius r in terms of x . and for the maximum areas is x=2/+4
Given that,
y forms a circle of radius r
y=2r
r=y/2
(2-y)- forms Square Side x
(2-y) = 4x
x=(2-y)/4
Now Sum of Area's=Area of Square +Area of Circle
Sum = r² + x²
Substitute the r and x values in above equation,
A(y)= y²/4+(y-2)²/ 16
To maximize Area A(y)
A'(y)= 0
2y/4 + 2(y-2)/16 =0
y/2 + (y-2)/8 =0
y = 2/
+4
Y max will be max, x to be maximum.
for maximum sum of areas,
x=2/+4
Hence,The formula for the radius r in terms of x . and for the maximum areas is x=2/+4
Learn more about Area :
#SPJ4
Answer:
(-4,-1)
Step-by-step explanation:
Assuming the graph is the one shown in the attachment.
The forward sloping line has a slope of 1 and a y-intercept of 3.
The equation of this line is y=x+3
The horizontal line has a slope of 0 and y-intercept of -1.
It's equation is y=-1
The two lines intersect at (-4,-1)
