<span>, y+2 = (x^2/2) - 2sin(y)
so we are taking the derivative y in respect to x so we have
dy/dx use chain rule on y
so y' = 2x/2 - 2cos(y)*y'
</span><span>Now rearrange it to solve for y'
y' = 2x/2 - 2cos(y)*y'
0 = x - 2cos(y)y' - y'
- x = 2cos(y)y' - y'
-x = y'(2cos(y) - 1)
-x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0
so when
f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1)
cos(0) = 1
thus
f'(2) = -2/(2(1)-1)
= -2/-1
= 2
f'(2) = 2
</span>
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Answer:
>
Step-by-step explanation:
π / 3 is in radians.
Radian need to be converted into
degree ( ° ).
The value of in degree is 180°
π / 3 = 180 / 3 = 60°
60° > 30°
So,
( π / 3 ) > 30°
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Answer:

Given line with an equation of y = 4x + 3
Parallel lines contain equivalent slopes, so a parallel line to the given equation would contain a slope of m = 4.
Plug in the coordinates of the point given, along with the slope into the equation y = mx + b where:
m = slope
y = y-coordinate of point
x = x-coordinate of point
Solve for the 'b' value, or y-intercept:
y = mx + b
6 = 4(2) + b
6 = 8 + b
b = -2
Rewrite the equation as slope-intercept form:
y = 4x - 2