Simplify
−
3
(
j
+
3
)
+
9
j
-
3
(
j
+
3
)
+
9
j
.
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Simplify each term.
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−
3
j
−
9
+
9
j
<
−
15
-
3
j
-
9
+
9
j
<
-
15
Add
−
3
j
-
3
j
and
9
j
9
j
.
6
j
−
9
<
−
15
6
j
-
9
<
-
15
Move all terms not containing
j
j
to the right side of the inequality.
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Add
9
9
to both sides of the inequality.
6
j
<
−
15
+
9
6
j
<
-
15
+
9
Add
−
15
-
15
and
9
9
.
6
j
<
−
6
6
j
<
-
6
Divide each term in
6
j
<
−
6
6
j
<
-
6
by
6
6
and simplify.
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Divide each term in
6
j
<
−
6
6
j
<
-
6
by
6
6
.
6
j
6
<
−
6
6
6
j
6
<
-
6
6
Simplify the left side.
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j
<
−
6
6
j
<
-
6
6
Simplify the right side.
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j
<
−
1
j
<
-
1
The result can be shown in multiple forms.
Inequality Form:
j
<
−
1
j
<
-
1
Interval Notation:
(
−
∞
,
−
1
)
Answer:
x = 0
Step-by-step explanation:
i) x - 11 + 1 < 15
x - 10 < 15
x < 10 + 15
x < 25
ii) x - 11 + 1 > 15
x - 10 > 15
x > 25
Therefore to compare (i) and (ii)
25 < x < 25
In any case, x = 0
Answer:f=10 and g(x)=4x
Step-by-step explanation:
The answer is C) 0.04 becuase the 4 is in the hundredths place
8y - 2 = - 18
8y = - 16
y = - 2
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