Answer:
x = (c + 6b)/3
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
-b + 3x = c + 5b
<u>Step 2: Solve for </u><em><u>x</u></em>
- Add <em>b</em> to both sides: 3x = c + 6b
- Divide 3 on both sides: x = (c + 6b)/3
Jacob is correct in thinking that because the mean represents the average of several quantities
Let that be

Two vertical asymptotes at -1 and 0

If we simply

- Denominator has degree 2
- Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
- But there should be a x intercept at -3 so one zeros should be -3
Find a equation
Find zeros
Horizontal asymptote
So our equation is

Graph attached
Answer:
sorry to answer late but..
Step-by-step explanation:
= 
the wings of the real plane are 12 meters or 1200 cm
we want to solve for the scale, sooo do the algebra...get scale by it self..
real *
= scale
1200 *
= 16
The scale model wings are 16 cm 2.54 cm is one inch so the wings are approx. 6.3 inches