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Ulleksa [173]
3 years ago
12

64 fl oz = _ c Plz answer

Mathematics
1 answer:
vaieri [72.5K]3 years ago
3 0
8oz= 1 cup
So 64oz= 8 cups
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nikklg [1K]

this is because 1lb is equal to 0.0625oz

4 0
3 years ago
Number seven on the page
prohojiy [21]
Multiply 9.75 by 1.5 to get 14.63 fluid ounces.
6 0
3 years ago
I need help on #15 and #16
Svetlanka [38]
Question 15:

\frac{3(x - 7)}{4} = x - 2

3(x -7) = 4(x - 2)

3x - 21 = 4x - 8

x = -13

Question 16:

7x - (5x - 1) = 2

7x -5x + 1 = 2

2x = 1

x = \frac{1}{2}
3 0
3 years ago
Read 2 more answers
What is the solution for -3x ≥ 36? x ≤ -12 x ≥ -12 x ≤ -108 x ≥ -108
konstantin123 [22]

Answer:

Step-by-step explanation:

Let  

V

be the number of vertices of a polyhedron,  

F

the number of faces of that polyhedron, and  

E

be the number of edges. The quantity  

χ

=

V

−

E

+

F

is called the Euler characteristic (of a polyhedron). In the case of convex polyhedra,  

χ

=

2

.

Consider, for example, a tetrahedron (which is the simplest solid). It has 4 faces,  

1

2

(

4

)

(

3

)

=

6

edges, and  

1

3

(

4

)

(

3

)

=

4

vertices. Thus we have  

V

−

E

+

F

=

4

−

6

+

4

=

2

.

Euler's formula holds for all Platonic solids (tetrahedron, cube, octahedron, dodecahedron, and icosahedron). Since a cube and an octahedron are dual polyhedra (each is formed by connecting the centers of the faces of the other), their  

V

and  

F

values are equal to the  

F

an  

V

values of the other. (The same is true for the dodecahedron and icosahedron).

3 0
3 years ago
Read 2 more answers
The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000
mel-nik [20]

Answer:

0.018 is the required probability.              

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 60,000 miles

Standard Deviation, σ = 1500 miles

We are given that the distribution of tread life is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(brand will last between 56,850 miles and 57,300 miles)

P(56850 \leq x \leq 57300) = P(\displaystyle\frac{56850 - 60000}{1500} \leq z \leq \displaystyle\frac{57300-60000}{1500}) = P(-2.1 \leq z \leq -1.8)\\\\= P(z \leq -1.8) - P(z < -2.1)\\= 0.0359 - 0.0179 = 0.018= 1.8\%

P(56850 \leq x \leq 57300) = 1.8\%

0.018 is the probability a certain tire of this brand will last between 56,850 miles and 57,300 miles.

7 0
4 years ago
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