I hope this helps you
distance=speed×time
first cars time t
second cars time t+3
same distance
distance=55.t
distance=40. (t+3)
55t=40 (t+3)
55t-40t=120
15t=120
t=8
t+3=11
Hmm, not sure
let me solve to make sure
so the lateral area=4*8+6*8+?*8
the ? is the hyptoonuse
remember
a^2+b^2=c^2
4^2+6^2=c^2
16+36=c^2
52=c^2
sqrt both sides
2√13=c
so
LA=4*8+6*8+8*2√13=
32+48+16√13=
80+16√13
the first blank is 80
2nd is 26
3rd is 13
Answer:
The height of the tree = 25 feet
Step-by-step explanation:
From the given diagram : EF = 5 feet, FA = 8 feet, CA = 40 feet
∠AFE = 90° and ∠ACB = 90°
To find : CB, the height of the tree.
Solution : In ΔAEF and ΔAB C
∠AFE = ∠ACB = 90°
∠A is common angle.
So, By AA postulate of similarity of triangle, ΔAEF ~ ΔABC
Now, sides of similar triangles are proportional to each other
Hence, The height of the tree = 25 feet
By dividing 24 and 4 to help you get your answer