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3 years ago

Nnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn

Mathematics

1 answer:

lianna [129]3 years ago

4 0

Answer:

That is not a question

Step-by-step explanation:

This is not a question that we can solve please put a REAL problom if you ever need help!

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What are the solutions of 12 - x2 = 0?

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Answer:

±2 sqrt(3) =x

Step-by-step explanation:

12 - x^2 = 0

Add x^2 to each side

12 - x^2 + x^2 = x^2

12 = x^2

Take the square root of each side

±sqrt(12) = sqrt(x^2)

±sqrt(4*3) = sqrt(x^2)

±sqrt(4) sqrt(3) = x

±2 sqrt(3) =x

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Which of the following values are zeros for the function below g(x)=(x2+4x-12)(x-3)

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Step-by-step explanation:

$g(x)=(x^2+4x-12)(x-3)=(x^2+6x-2x-12)(x-3)\\\\=[x(x+6)-2(x+6)](x-3)=(x+6)(x-2)(x-3)\\\\\text{The zeros for}\ g(x)=0:\\\\(x+6)(x-2)(x-3)=0\iff x+6=0\ \vee\ x-2=0\ \vee\ x-3=0\\\\x=-6\ \vee\ x=2\ \vee\ x=3$

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