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SVEN [57.7K]
3 years ago
15

What is the value of x? (3x + 50) Enter your answer in the box. (6x - 10 x =

Mathematics
1 answer:
Zanzabum3 years ago
3 0

I think the value of x is 20°.

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PLEASE HELP ME WITH THIS QUESTION ITS URGENT!!!
Alex Ar [27]

Start by distributing the exponent to each of the terms in (2u)^{3}.  This will become 2^{3} u^{3}, and 2^{3} =8.  Now, the expression is:

\frac{2u^{3} v^{2} }{8u^{3} * u^{2} }.


We can now simplify the bottom to read: 8u^{5} because when multiplying variables raised to an exponent, we add the exponents.  The expression now looks like:

\frac{2u^{3} v^{2} }{8u^{5} }


The 2/8 simplifies to 1/4:

\frac{u^{3} v^{2} }{4u^{5} }


Now, we have two u terms on the top and bottom.  When dividing variables raised to an exponent, we subtract the exponents.  However, since 3-5=-2, the term will be on the bottom to avoid the negative exponent.  The final answer is:

\frac{v^{2} }{4u^{2} }


Hope this makes sense!!


4 0
4 years ago
Need help with math ASAP (Please)
Scrat [10]
First you plot in the y-intercept of the equation. To find the y-intercept, substitute 0 into x. -3m will cancel our giving you y=5. x=0, y=5, the first ordered pair is (0,5). Now after you plot in the y-intercept, use your slope, which is -3, to graph the points of the equation. Starting from (0,5), move down 3 spaces on the y-axis (because it’s -3) and you’ll end up at (0,2). Next move over 1 ( all slopes with just a whole number moves on the x-axis 1 since the whole number divided by 1 doesn’t change the slope number) to the right because it’s a negative linear equation so it’ll go downward. After moving right, you’ll get (1,2). Do a couple more points starting from (1,2) then the 3rd point ABD and so on to get 3 or more points to be able to draw a linear line.
7 0
3 years ago
Read 2 more answers
A dog weighs 35.4 kilograms.1 kilogram=2.2 pounds,1 pound=0.45 kilograms.About how much does the dog weigh in pounds?Round to ne
AlladinOne [14]
Answer: 78 pounds
Explanation: if 1 kilogram is 2.2 pounds, just multiply the weight in kg by 2.2:
35.4 x 2.2 = 77.88
Round to nearest whole: 78.
So the dog is 78 pounds
4 0
2 years ago
Read 2 more answers
If the radius of the circle is multiplied by a factor of 3, then the area of the circle is multiplied by a factor of
Oksi-84 [34.3K]
\bf \textit{area of a circle}\\\\
A=\pi r^2\quad 
\begin{cases}
r=radius\\
-----\\
r=\stackrel{r\times 3}{3r}
\end{cases}\implies A=\pi (3r)^2
\\\\\\
A=\pi (3^2r^2)\implies A=9(\pi r^2)

notice, if the original area was πr², then the new area has a factor in front of it, that much.
8 0
3 years ago
Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.
loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>
  • x^ax^b = x^{(a+b)}
  • \dfrac{x^a}{x^b} = x^{(a-b)}
  • (a^a)^b =x^{(a\times b)}
  • (xy)^a = x^ay^a
  • x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4

The solution of the expression is \dfrac{4x^4}{y^6}.

<h2>Explanation</h2>

Given to us

  • (16x^8y^{12})^{\frac{1}{2}}

Solution

We know that 16 can be reduced to 2^4,

=(2^4x^8y^{12})^{\frac{1}{2}}

Using identity (xy)^a = x^ay^a,

=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}

Using identity (a^a)^b =x^{(a\times b)},

=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})

Solving further

=2^2x^4y^{-6}

Using identity \dfrac{x^a}{x^b} = x^{(a-b)},

=\dfrac{2^2x^4}{y^6}

=\dfrac{4x^4}{y^6}

Hence, the solution of the expression is \dfrac{4x^4}{y^6}.

Learn more about Exponentiation:

brainly.com/question/2193820

8 0
2 years ago
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