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3 years ago

What is the slope of the line 3х + 5у — 2х + Зу

Mathematics

1 answer:

Shkiper50 [21]3 years ago

8 0

Answer:

-1/8

Step-by-step explanation:

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Plz help it’s due tonight!!!

jasenka [17]

sorry

Step-by-step explanation:

4 0

2 years ago

Using the image, determine the length of each arc. m RC= m CBR =

Montano1993 [528]

Given:

Given that the measure of ∠CDR = 85°

We need to determine the measure of $\widehat{RC}$ and $\widehat{CBR}$

Measure of arc RC:

Since, we know that if a central angle is formed by two radii of the circle then the central angle is equal to the intercepted arc.

Thus, we have;

$m\angle CDR = m \widehat{RC}$

Substituting the values, we get;

$85^{\circ} = m \widehat{RC}$

Thus, the measure of $\widehat{RC}$ is 85°

Measure of arc CBR:

We know that 360° forms a full circle and to determine the measure of arc CBR, let us subtract the values 360 and 85.

Thus, we have;

$m\widehat{CBR}=360^{\circ}-m \widehat{RC}$

Substituting the values, we have;

$m\widehat{CBR}=360^{\circ}-85^{\circ}$

$m\widehat{CBR}=275^{\circ}$

Thus, the measure of $\widehat{CBR}$ is 275°

6 0

3 years ago

Find the value of 4th terms by using 3n-2

Serga [27]

10 is the answer I think

7 0

3 years ago

Read 2 more answers

1-58. Mr. Wright was making a table to figure out how much it costs to send a certain numt

Drupady [299]

A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Given that

$\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]$

Let:

$L \to$ Letters

$C \to$ Cost

Using proportional reasoning, we have:

$C = kL$

Where

$k \to$ ratio of proportion

For the first values of C and L, we have:

$C = kL$

$0.45 = k \times 10$

Divide both sides by 10

$k = 0.045$

So, the equation of proportion is:

$C = 0.045L$

When C = 6.75, we have:

$C = 0.045L$

$6.75 = 0.045L$

Solve for L

$L = \frac{6.75}{0.045}$

$L = 150$

When L = 7, we have:

$C = 0.045L$

$C = 0.045 \times 7$

$C = 0.315$

When L = 1, we have:

$C = 0.045L$

$C = 0.045 \times 1$

$C = 0.045$

When L = 500, we have:

$C =0.045L\\$

$C =0.045 \times 500$

$C =22.5$

When C = 18.90, we have:

$C = 0.045L$

$18.90 = 0.045L$

Solve for L

$L=\frac{18.90}{0.045}$

$L=420$

Hence, the complete table is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$