All categories

4 years ago

Suppose the graph of direct variation y=(2m-1)x passes through Quadrants II and IV. Then find the range of m.

Mathematics

1 answer:

Alenkinab [10]4 years ago

3 0

If y = (2m - 1)x passes through quadrants II and IV, then 2m - 1 < 0.
∴ 2m < 1
∴ m < $\frac{1}{2}$

You might be interested in

What is the length of XY?

liubo4ka [24]

Answer: The length of $XY$ is 30.

Step-by-step explanation:

-According to the figure, Δ $XYZ$ is congruent to Δ $XWZ$ .

So, if the length of $WX$ is 30, then the length of $XY$ is also 30, because $WX = XY$ .

7 0

4 years ago

Help plzzz on edge i have almost 50 mins to complete

kherson [118]

Answer:

m=2 (0,4)

Step-by-step explanation:

3 0

3 years ago

Blah blah blah Help me please!!!

Roman55 [17]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Encontrar el valor d la variable

Yuki888 [10]

I think it may be 5+3 and carry the one up top to get the sum of 56.

7 0

3 years ago

Solve for x! 37m,12m,5xm

dmitriy555 [2]

Answer:

$\Huge\boxed{x=7}$

Step-by-step explanation:

Hello there!

The first thing we want to do is find the measure of the large leg

To do so we use the Pythagorean theorem which says $a^2+b^2=c^2\\$

where a and b are legs and c is the hypotenuse

we want to find b given the hypotenuse and short leg

so $b^2=c^2-a^2$

all we have to do is plug in a ( a = short leg so a would equal 12) and c ( c = hypotenuse so c would equal 37)

$b^2=37^2-12^2\\37^2=1369\\12^2=144\\1369-144=1225\\b^2=1225\\\sqrt{b^2} =b\\\sqrt{1225} =35\\b=35$

so the longer leg is equal to 35

35=5x

divide each side by 5

5x/5=x

35/5=7

we're left with x=7

3 0

3 years ago