Answer:
C.
Explanation:
A peeler removes fruit and vegetable skins in small strips.
Let us assume number of toppings = n
Total weight of sundae = s
Quantity of Ice cream = 2 kilograms.
We need to discribe the total weight of the special sundae in kilograms by an inequality.
The sundae contains ice cream and number of toppings.
So the total weight of the sundae will be greater than the total weight of ice cream and number of toppings, because there would be some weight of the packing.
Therefore,
The total weight of the sundae > total weight of ice cream + weight of toppings.
s > 2 + n.
Where, s is the total weight of the sundae and n is the weight of toppings. I hope this was helpful!. :)
Answer:
2440.24 J
Explanation:
Moment of inertia, I1 = 5 kg m^2
frequency, f1 = 3 rps
ω1 = 2 x π x f1 = 2 x π x 3 = 6 π rad/s
Moment of inertia, I2 = 2 kg m^2
Let the new frequency is f2.
ω2 = 2 x π x f2
here no external torque is applied, so the angular momentum remains constant.
I1 x ω1 = I2 x ω2
5 x 6 π = 2 x 2 x π x f2
f2 = 7.5 rps
ω2 = 2 x π x 7.5 = 15 π
Initial kinetic energy, K1 = 1/2 x I1 x ω1^2 = 0.5 x 5 x (6 π)² = 887.36 J
Final kinetic energy, K2 = 1/2 x I2 x ω2^2 = 0.5 x 3 x (15 π)² = 3327.6 J
Work done, W = Change in kinetic energy = 3327.6 - 887.36 = 2440.24 J
